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iragen [17]
2 years ago
10

Given a ≠ ± b and (a^2-b^2) / (a+b)=12 find a-b.

Mathematics
1 answer:
grigory [225]2 years ago
5 0

Answer:

\sqrt{12a  \:  +  \: 12b \:  -  \: 2ab \:  +  \: 2b {}^{2} }

Step-by-step explanation:

(a²-b²) / (a+b) = 12

a² - b² = 12(a+b)

(a-b)² + 2ab - 2b² = 12a + 12b

(a-b)² = 12a + 12b - 2ab + 2b²

a - b =

\sqrt{12a \:  + 12b \:  - 2ab \:  +  \: 2b {}^{2} }

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