<h3>The volume of cube is 729 cubic centimeter</h3>
<em><u>Solution:</u></em>
<em><u>The surface area of cube is given as:</u></em>

Where, "a" is the length of side of cube
Given that, surface area = 486 square centimeter

<u><em>Find the volume of cube:</em></u>

Thus volume of cube is 729 cubic centimeter
Answer:
x=27 km
Step-by-step explanation:
Make an equation 2/.015=3600/x
Multiply 3600 by .015 to get 54
Divide 54 by 2 to get 27.
Answer:
The answer to your question is
a) Poster width = 3 in
lenght = 9 in
b) banner
width = 2 in
lenght = 10 in
Step-by-step explanation:
a) For the poster
width = x
lenght = 3x
Perimeter of a rectangle = 2base + 2 height
= 2(x) + 2(3x) = 24
2x + 6x = 24
8x = 24
x = 24/8
x = 3
width = 3 in
lenght = 3(3) = 9 in
b) For the banner
width = y
lenght = 5y
Perimeter of a banner = 2 base + 2 height
2 (y) + 2(5y) = 24
2y + 10y = 24
12y = 24
y = 24/12
y = 2
width = 2 in
lenght = 5(2) = 10 in
Since the area of a square is equal to the square of one of its side's length, then the area should be equivalent to

.

---> equation (1)
By using pythagoras rule which states that the

---> equation (2)
where the opposite side's length is 8 and the hypotenuse side's length is 10
by substituting by the values in equation (2) therefore,

substitute this value in equation (1) then

where A is the area of the square whose side is x