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Naddik [55]
3 years ago
11

What has prompted you to borrow money from friends or family?

Mathematics
2 answers:
Tcecarenko [31]3 years ago
6 0

Answer:

I needed money  to buy stuff at the mall with my friends because I didn't want to spend my own... :/ lol

Sindrei [870]3 years ago
5 0
So I want have to spend my on :)
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Please help ASAP!!! Will give brainlist :)
fgiga [73]

Answer:

A': (-1,3)

B': (-4,5)

C': (-3,1)

x-coordinate gets multiplied by -1.

y-coordinate remains unchanged

6 0
3 years ago
Find the area of the composite figure.<br> 21 ft<br> 12 ft<br> 9 ft<br> 9 ft<br> 6 ft<br> 6 ft
nydimaria [60]

Answer:

738 square ft

Step-by-step explanation:

Area of the composite figure

= 21*(12 + 9 + 6) + 9*(9 + 6) + 6*6

= 21*27 + 9*15 + 6*6

= 567 + 135 + 36

= 738 square ft

7 0
3 years ago
Find the area of the shape shown<br> below.
Allisa [31]

Answer:

The area of the figure is 28 units².

Step-by-step explanation:

Find the area of the full rectangle, ignoring the triangle.

a = lw \\ a = 4 \times 8 = 32

Then, find the area of the triangle:

a =  \frac{bh}{2}  \\ a =  \frac{2 \times 4}{2}  \\ a = 4

Finally, subtract:

32 - 4 = 28

7 0
3 years ago
41. Two antenna towers, 400 m apart, are to be supported by a single cable anchored at a common point between them. One tower is
Ghella [55]

Answer:

The anchor should be located at the midpoint between the 20m high and 60m high antennas.

Step-by-step explanation:

Let the length of cable for 20m high antenna be represented by x, and that for 60m high antenna be y.

The single length of cable required = x + y.

From the principle of geometry, if the cable is anchored at 200m from the 20m high antenna, it forms a right angled triangle. Applying the Pythagoras theorem,

x = \sqrt{200^{2} - 20^{2} }

 = 199

Applying the same principle to the 60m high antenna gives,

y = \sqrt{200^{2} - 60^{2} }

 = 191

The single length of cable required = 199+  191

                                                           = 390m

Varying the point of location of the anchor between the two antennas causes an increase in the length of cable required.

The anchor should be located at the midpoint between the two antennas to achieve a minimum amount of cable.

5 0
4 years ago
Jimmy invests $3000 in an account with a 3.8% interest rate, making no other deposits or withdrawals. What will Jimmy’s account
Leto [7]
Use the formula A(t)=P(1+[r/n])^(n)(t) which for us looks like this:
A(t)= 3000(1+[.038/4])^(4)(9). Doing that math, you have 3000(1.405489). The product of that is $4216.47
4 0
4 years ago
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