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3 years ago

Why does the shape of the distribution of the weights of russet potatoes tend to be symmetrical?

Mathematics

2 answers:

Sergio [31]3 years ago

6 0

Answer:

Mean ≈ Median

Anon25 [30]3 years ago

5 0

Answer:

The shape of the distribution of the weights of russet potatoes tends to be symmetrical because the

mean = median

Step-by-step explanation:

Shape of distribution is determined by the number of peaks a distribution has, the presence of symmetry and its ability to be uniform or skewed.

We have various types of shape of distribution

a. Left skewed shape of distribution

b. Right skewed shape of distribution.

c. Symmetrical shape of distribution

d. Bimodal or Uniform shape of distribution.

Symmetrical shape of distribution occurs when the mean and the median of the distribution occur at the same point or area, hence they are same or equal to one another.

Therefore, the shape of the distribution of the weights of russet potatoes tends to be symmetrical because the Mean is equal to the Median because they occur at the same point.

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9×3 n =3 powered by 7 slove n

aleksandrvk [35]

Answer:

Step-by-step explanation:

9 × 3n= 3^7

9×3n= 2187

27n= 2187

n= 2187/27

= 81

Hence n= 81

5 0

3 years ago

An observer (0) spots a plane flying a 35° angle to his horizontal line of the sight. If the plane is flying at an altitude of 1

ella [17]

Refer to the diagram shown below.

By definition,
sin(35°) = 17000/x
Therefore
x = 17000/sin(35°) = 29,638.6 ft

Answer: 29,638.6 ft

6 0

3 years ago

Which expression is a difference of cubes? 9w^33-y^12 18p^15-q^21 36a^22-b^16 64c^15- a^26

LiRa [457]

we know that

A polynomial in the form $a^{3}-b^{3}$ is called adifference of cubes. Both terms must be a perfect cubes

Let's verify each case to determine the solution to the problem

case A) $9w^{33} -y^{12}$

we know that

$9=3^{2}$ ------> the term is not a perfect cube

$w^{33}=(w^{11})^{3}$ ------> the term is a perfect cube

$y^{12}=(y^{4})^{3}$ ------> the term is a perfect cube

therefore

The expression $9w^{33} -y^{12}$ is not a difference of cubes because the term $9$ is not a perfect cube

case B) $18p^{15} -q^{21}$

we know that

$18=2*3^{2}$ ------> the term is not a perfect cube

$p^{15}=(p^{5})^{3}$ ------> the term is a perfect cube

$q^{21}=(q^{7})^{3}$ ------> the term is a perfect cube

therefore

The expression $18p^{15} -q^{21}$ is not a difference of cubes because the term $18$ is not a perfect cube

case C) $36a^{22} -b^{16}$

we know that

$36=2^{2}*3^{2}$ ------> the term is not a perfect cube

$a^{22}$ ------> the term is not a perfect cube

$b^{16}$ ------> the term is not a perfect cube

therefore

The expression $36a^{22} -b^{16}$ is not a difference of cubes because all terms are not perfect cubes

case D) $64c^{15} -a^{26}$

we know that

$64=2^{6}=(2^{2})^{3}$ ------> the term is a perfect cube

$c^{15}=(c^{5})^{3}$ ------> the term is a perfect cube

$a^{26}$ ------> the term is not a perfect cube

therefore

The expression $64c^{15} -a^{26}$ is not a difference of cubes because the term $a^{26}$ is not a perfect cube

I'm adding a new case so I can better explain the problem

case E) $64c^{15} -d^{27}$

we know that

$64=2^{6}=(2^{2})^{3}$ ------> the term is a perfect cube

$c^{15}=(c^{5})^{3}$ ------> the term is a perfect cube

$d^{27}=(d^{9})^{3}$ ------> the term is a perfect cube

Substitute

$64c^{15} -d^{27}=((2^{2})(c^{5}))^{3}-(d^{9})^{3}$

therefore

The expression $64c^{15} -d^{27}$ is a difference of cubes because all terms are perfect cubes

5 0

3 years ago

Read 2 more answers

Is 8/10 an irrational number

bearhunter [10]

8/10 is usually written 4/5, so yes it is irrational.

7 0

3 years ago

One attorney claims that more than 25% of all the lawyers in Boston advertise for their business. A sample of 200 lawyers in Bos

icang [17]

Answer:

There is enough evidence to support the attorney’s claim

Step-by-step explanation:

Given that one attorney claims that more than 25% of all the lawyers in Boston advertise for their business.

Sample size n =200

Sample proportion = $63/200=0.315$

Hypotheses:

$H_0: p=0.25\\H_a: p>0.25$

(right tailed testat 5% significance level)

Assuming H0 to be true, std error of p = $\sqrt{0.25*0.75/200 \\=0.0306$

Test statistic z = p diff/std error

= $\frac{0.315-0.25}{0.0306} \\=2.12$

p value for one tailed =0.0170

Since p <0.05 we reject null hypothesis

There is enough evidence to support the attorney’s claim

5 0

3 years ago