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Sergio [31]
3 years ago
5

The rule R x-axis ∘ T⟨–5, 3⟩ is applied to the point (–3, –2). Where is the image in the coordinate system?

Mathematics
1 answer:
ollegr [7]3 years ago
3 0

Given:

Rule of transformation is rule R x-axis ∘ T⟨–5, 3⟩.

The point is (-3,-2).

To find:

The image of given point after the transformation.

Solution:

Consider the given point be P(-3,-2).

Rule of transformation is rule R x-axis ∘ T⟨–5, 3⟩. If means first we have apply translation T⟨–5, 3⟩ after that we have to apply reflection R x-axis.

If a figure translated by T⟨–5, 3⟩, then

(x,y)\to (x-5,y+3)

P(-3,-2)\to P'(-3-5,-2+3)

P(-3,-2)\to P'(-8,1)

If a figure reflected by R x-axis, then

(x,y)\to (x,-y)

P'(-8,1)\to P''(-8,-1)

Therefore, the image of given point after transformation is (-8,-1).

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Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}    

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n_{1}=1000 sample 1 selected  

n_{2}=900 sample 2 selected  

p_{1}=\frac{410}{1000}=0.410 represent the proportion estimated of people indicating that their financial security was more than fair in 2012

p_{2}=\frac{315}{900}=0.350 represent the proportion estimated of people indicating that their financial security was more than fair in 2010  

\hat p represent the pooled estimate of p

z would represent the statistic (variable of interest)    

p_v represent the value for the test (variable of interest)  

\alpha=0.05 significance level given  

Part a: Concepts and formulas to use    

We need to conduct a hypothesis in order to check if is there is a difference between the two proportions, the system of hypothesis would be:    

Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}    

Hypothesis testing

We need to apply a z test to compare proportions, and the statistic is given by:    

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{410+315}{1000+900}=0.382  

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.    

Calculate the statistic  

Replacing in formula (1) the values obtained we got this:    

z=\frac{0.410-0.350}{\sqrt{0.382(1-0.382)(\frac{1}{1000}+\frac{1}{900})}}=2.688    

Statistical decision  

Since is a two sided test the p value would be:    

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Comparing the p value with the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to to reject the null hypothesis, and we can say that the proportions analyzed are significantly different at 5% of significance.

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