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atroni [7]
3 years ago
6

How many times larger is 4×10^12 than 8×10^7?2×10^42×10^55×10^45×10^5​

Mathematics
1 answer:
Leno4ka [110]3 years ago
6 0
The answer is 5×10^4
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A: 5x − 2y = 10
Nuetrik [128]

Answer:

D) Multiply A by -4 and B by 5

Step-by-step explanation:

5x-2y=10

4x+3y=7

----------------

-4(5x-2y)=-4(10)

5(4x+3y)=5(7)

----------------------

-20x+8y=-40

20x+15y=35

---------------------

23y=-5

y=-5/23

5x-2(-5/23)=10

5x+10/23=10

5x=10-10/23

5x=230/23-10/23

5x=220/23

x=(220/23)/5

x=(220/23)(1/5)

x=220/115

x=44/23

7 0
4 years ago
Pls, help! I don't understand this!
aliya0001 [1]
2. the scale factor is x= 4.5 cm
this is because when u see how much it dilated from 4cm to 2cm it divided from 2, so if u did the same for the other number. Which is 9, it’s 9/2 which equals 4.5
4 0
3 years ago
Read 2 more answers
In which quadrant does -8,-10 lie?
masya89 [10]

Answer:

The point (-8,-10) lies in the third quadrant of the graph.

Step-by-step explanation:

I graphed the point below to show that it is in the third quadrant.

If this answer is correct, please make me Brainliest!

5 0
4 years ago
Rectangle ABCD is similar to Rectangle WXYZ.
adell [148]
This is true as the ratio of area is equal to ratio of sides squared
5 0
4 years ago
Inverse variation?
Alex_Xolod [135]

Answer:

An Inverse variation states that a relationship between two variables in which the product is always constant.

If one of the variable increases then the other decreases in proportion so that the product is unchanged.

if y is inversely proportional to x, then the equation is of the form

y = \frac{k}{x} , where k is constant.

As per the given condition, A constant force acts upon an object, the acceleration of the object varies inversely with it's mass.

i.e, a \propto \frac{1}{m}

By definition of inverse variation;

a = \frac{F}{m} . ......[1]  ,where F is the constant force.

It is given that an object has mass(m)= 4kg and the acceleration of an object(a) = 14 m/s^2

Substitute these in [1] to find the constant force F;

14 = \frac{F}{4}

or

F =14 \times 4 = 56 kg m/s^2

Now, if the same force acts upon the another object whose mass (m) = 7 kg then calculate acceleration.

[1]⇒  a = \frac{56}{7} = 8 m/s^2

therefore, the acceleration of an another object is, 8 m/s^2


3 0
4 years ago
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