Answer:
a) 0.07203
b) 0.0189
c) 0.973
Step-by-step explanation:
Probability of making one shot, for the player = 70% = 0.70
Probability of NOT making a shot = 1 - 0.70 = 0.30
Assuming that the shots are independent
a) Misses for the first time on his fifth attempt
For him to miss on his for the first time on his fifth attempt, he has to make the first four shots
The required probability = (0.7)⁴(0.3) = 0.07203
b) Makes his first basket on his fourth shot
For him to make his first basket on the fourth shot, he has to miss the first three shots.
Required probability = (0.3)³(0.7) = 0.0189
c) Makes his first basket on one of his first 3 shots
This is a sum of probabilities; that is, he could make the first basket on the first shot, or miss on the first shot and make the second shot or miss on the first two shots and make the basket on the third shot.
Required probability
= (0.70) + (0.3×0.7) + (0.3×0.3×0.7)
= 0.70 + 0.21 + 0.063 = 0.973
Hope this Helps!!!
