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Luba_88 [7]
3 years ago
14

You have been doing a lot of web surfing lately as part of your research for your course and along the way you have noticed a gr

owing number of active server pages. You have a good head for technical details and ask your friend Laura to enlighten you about some of the finer points of ASP technology.
Which of the following does Laura tell you is NOT a component of the active server page?
a. the generated code component that executes on the web server
b. the HTML component that is interpreted and executed by a web browser
c. the database engine that generates the form
d. All of the above are components of the active server page.
Computers and Technology
1 answer:
creativ13 [48]3 years ago
3 0

The generated code component that executes on the web server is the following does Laura tell you is NOT a component of the active server page.

a. the generated code component that executes on the web server

<u>Explanation:</u>

Asp technology is where it is a combination of both  HTML and visual basic programming. Asp web pages are executed in server and display as Html to the end-users.

With the HTML coding, only static pages can be developed whereas through ASP web pages are developed and which contains visual basic coding languages and for client-side validates in ASP web pages either javascript or visual basic scripts are used.

Each ASP web pages are compiled at the server end and executed and complied out HTML pages are shown in web pages.

We need to install the ASP component at the server to execute the ASP web pages.

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Roman55 [17]

Answer:

It might helpful or might be the correct answer to provide the complete question or problem:

This is a testbench design problem, within it, you need to consider the module describing an accumulator.

Explanation:

Consider the following module describing an accumulator:

module  accumulator (

       output reg:  [ 15:0 ]   sum,     // acumulated out

       input [ 7:0 ] in,                      //in

       input rst / clk ) ;                   //reset and clock inputs

       wire  carry ;

       wire [ 15:0 ] sum_in ;

       assign  { carry , sum_in } =  sum + in ;

        alwaysatt ( posedge clock )

                 if ( rst ) sum ∠ = 0 ; else

                 sum ∠ = ( carry ) ?  16´hFFFF  :   sum_in ;

endmodule

From the design code, these are the specifications:

- An active high reset ( rst ) that is synchronous to the positive edge of the clock ( clk ) and clears the output ( sum ) to zero.

- Once reset is removed, the accumulator accumulates summation of the data present on the input ( in ) on every positive clock edge and if the summation exceeds the maximum value that can be represented using a 16-bit number (i.e. 16´hFFFF), the output gets saturated at 16´hFFFF

- The design treats the input data as an unsigned number and produces the output also as unsigned value.

Now write a complete system verilog for this desing that:

(See  1, 2, 3, 4, 5, 6, 7, 8 system requirements)

Defines and uses an interface block to connect to the test program and the DUT.

The interface block should also contain a clocking block and modport statements for defining signal direction to the testbench and to the DUT.

2. Generates the clock signal

3. Applies reset at the beginning

4. Checks the success of the reset operation and displays a success/fail message

5. Makes use of a class for defining random variables and a dynamic array to hold the random values.

6. Constraints the generated random values such that the number of generated random values (i.e. size of dynamic array) is less than 500 and their sum will be greater than 16'hFFFF

7. Applies the generated random values to the design input (in), one at every clock cycle

8. Checks the correctness of the design output (sum) at every clock cycle while applying inputs, and reports if there is a mismatch between the output of the design and the expected output.  

 

Explanation:

 

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