Question

A Triangle pqs such that angle psq=68°pq is ptoduced to R such that angle RQS=146° calculate the size of angle SPQ and SQR

Answer 1

Answer: (i) SPQ = $78^{0}$

(ii) SQR = 146°

Step-by-step explanation:

<SPQ = 146 - 68 = $78^{0}$ ( the exterior angle of a triangle is equal to the sum of the two opposite interior angle )

RQS is the exterior angle

The opposite interior angles are PSQ and SPQ , from the theorem :

PSQ + SPQ = RQS , that is

68 + SPQ = 146

SPQ = 146 - 68

SPQ = $78^{0}$

(ii) SQR = RQS

Therefore : SQR = 146°