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3 years ago

If x/y = -3, then find x²/y² + y²/x².

Mathematics

1 answer:

sladkih [1.3K]3 years ago

6 0

Answer:

9.11

Step-by-step explanation:

Given that,

$\dfrac{x}{y}=-3$

We need to find the value of $\dfrac{x^2}{y^2}+\dfrac{y^2}{x^2}$

The value of $\dfrac{y}{x}=\dfrac{-1}{3}$

So,

$\dfrac{x^2}{y^2}+\dfrac{y^2}{x^2}=(\dfrac{x}{y})^2+(\dfrac{y}{x})^2\\\\=(-3)^2+(\dfrac{-1}{3})^2\\\\=9+\dfrac{1}{9}\\\\=9.11$

So, the required answer is equal to 9.11.

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3 years ago

What property in math does 20-20=0 go on????? This is my sisters homework question....

zimovet [89]

Isn't the "Property of Subtraction,"?

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3 years ago

What the answer for the question

Goryan [66]

Answer:

9/14

Step-by-step explanation:

(3/7)/(2/3) Flip the sign of the second term and multiply.

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3 years ago

Read 2 more answers

A small publishing company is planning to publish a new book. The production costs will include one-time fixed costs (such as ed

zhuklara [117]

Answer:

For the cost from the two methods to be equal, 3,200 books have to be produced

Step-by-step explanation:

In this question, we are asked to calculate the number of books that will be produced for two methods of production having different fixed and variable costs to have the same production cost.

Since the number of books is something we do not know, let’s represent it with a variable called c.

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Now since they are said to be equal, we proceed to equate both;

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4 0

3 years ago

Pls help me factorize.Thanks!

Nat2105 [25]

We can change the sign of the second term, so that the two parenthesis are the same:

$6(a-1)b^3+3(1-a)b^2 = 6(a-1)b^3-3(a-1)b^2$

Now, both terms have in common a 3, becase the numeric factors are 3 and 6. If we factor the 3, we have

$6(a-1)b^3-3(a-1)b^2 = 3(2(a-1)b^3-(a-1)b^2)$

The parenthesis (a-1) is also in common, so we can factor it as well:

$3(2(a-1)b^3-(a-1)b^2) = 3(a-1)(2b^3-b^2)$

Finally, both terms in the parenthesis contain $b^2$ , because it's the power of b with the lowest exponent:

$3(a-1)(2b^3-b^2) =3(a-1)b^2(2b-1)$

So, the factorization is

$3b^2(a-1)(2b-1)$

You can swap the order of the four factors (3, b^2, a-1 and 2b-1) as you like: the multiplication is commutative.

5 0

3 years ago

If x/y = -3, then find x²/y² + y²/x².​

If x/y = -3, then find x²/y² + y²/x².