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Rzqust [24]
3 years ago
10

Can u help pretty pls and fast thank you

Mathematics
1 answer:
adoni [48]3 years ago
6 0

Answer: 20% Percent Discount

Step-by-step explanation:

$800.00 - $640.00=$160.00 / $800.00= .2 or 20%

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HELP ME!!! Answer in Scientific Notation and explain and show work.
umka21 [38]
Multiplying means you add the exponents and dividing means you subtract the exponents. Treat the decimals as you normally would.
(4.3 \times  {10}^{8} ) \times (2.0 \times  {10}^{6} )
4.3 \times 2.0 = 8.6
8 + 6 = 14
8.6 \times  {10}^{14}

(6 \times  {10}^{3} ) \times (1.5 \times  {10}^{ - 2} )
6 \times 1.5 = 9
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(1.5 \times  {10}^{ - 2} ) \times (8.0 \times  {10}^{ - 1} )
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\frac{6.48 \times  {10}^{5} }{(2.4 \times  {10}^{4} )(1.8 \times  {10}^{ - 2}) }
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\frac{6.48 \times  {10}^{5} }{4.32 \times  {10}^{2} }
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7 0
3 years ago
According to the US Bureau of Labor Statistics publication News, self-employed persons with home-based businesses work a mean of
worty [1.4K]

Answer:

The answer is below

Step-by-step explanation:

Given that mean (μ) = 23 hours, standard deviation (σ) = 10 hours

a) The population is a group of self employed home based workers while the variable is the number of hours worked per week.

b) The mean of the distribution of sample means (also known as the Expected value of M) is equal to the population mean μ.

\mu_x=\mu=23\ hours

The standard deviation of the distribution of sample means is called the Standard Error of M, it is given by:

\sigma_x=\sigma/\sqrt{n} =\frac{10}{\sqrt{100} }=1

c) \mu_x=\mu=23\ hours

\sigma_x=\sigma/\sqrt{n} =\frac{10}{\sqrt{1000} }=0.32

d) The sample size has no effect on the mean, hence increasing the sample size does not change the mean.

The square root of sample size is inversely proportional to the standard deviation therefore increasing the sample size reduces the standard deviation.

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