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Hatshy [7]
2 years ago
12

Reduce the fractions using the greatest common factor 7 over 12

Mathematics
1 answer:
Airida [17]2 years ago
4 0

Answer:

7/12 cannot be reduced

Step-by-step explanation:

7 = 7

12 = 2 * 2 * 3

7 and 12 have no common factors other than 1, so the fraction 7/12 cannot be reduced. 7/12 is already written in lowest terms.

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Polly's Polls asked 1850 second-year college students if they still had their original major. According to the colleges, 65% of
suter [353]

Answer:

The probability that Polly's Sample will give a result within 1% of the value 65% is 0.6424

Step-by-step explanation:

The variable that assigns the value 1 if a person had its original major and 0 otherwise is a Bernoulli variable with paramenter 0.65. Since she asked the question to 1850 people, then the number of students that will have their original major is a Binomial random variable with parameters n = 1850, p = 0.65.

Since the sample is large enough, we can use the Central Limit Theorem to approximate that random variable to a Normal random variable, which we will denote X.

The parameters of X are determined with the mean and standard deviation of the Binomal that we are approximating. The mean is np = 1850*0.65 = 1202.5, and the standard deviation is √np(1-p) = √(1202.5*0.35) = 20.5152.

We want to know the probability that X is between 0.64*1850 = 1184 and 0.66*1850 = 1221 (that is, the percentage is between 64 and 66). In order to calculate this, we standarize X so that we can work with a standard normal random variable W ≈ N(0,1). The standarization is obtained by substracting the mean from X and dividing the result by the standard deviation, in other words

W = \frac{X-\lambda}{\sigma} = \frac{X-1202.5}{20.5152}

The values of the cummulative function of the standard normal variable W, which we will denote \phi are tabulated and they can be found in the attached file.

Now, we are ready to compute the probability that X is between 1184 and 1221. Remember that, since the standard random variable is symmetric through 0, then \phi(-z) = 1-\phi(z) for each positive value z.

P(1184 < X < 1221) = P(\frac{1184-1202.5}{20.5152} < \frac{X-1202.5}{20.5152} < \frac{1221-1202.5}{20.5152})\\ = P(-0.9018 < W < 0.9018) = \phi(0.9018) - \phi(-0.9018) = \phi(0.9018)-(1-\phi(0.9018))\\ = 2\phi(0.9018)-1 = 2*0.8212-1 = 0.6424

Therefore, the probability that Polly's Sample will give a result within 1% of the value 65% is 0.6424.

Download pdf
4 0
3 years ago
How do I to problems like "From 45 ft to 92 ft"?
djyliett [7]

Answer:

45tf+47tf=92tf

Step-by-step explanation:

I hope this help you out♊♊ tell me is this correct♊♊♊

3 0
3 years ago
Manuel and Joe order pasta for $4.55, salad for $5.15, and 2 glasses of lemonade for $1.70 each. The tax is $1.05. How much chan
Svetradugi [14.3K]
They should get 85 cents. ($0.85)
7 0
3 years ago
A + b + c =-10 <br> x + y + z =-10<br><br> what is <br> −6c−6b+6z+6x+6y−6a?
shutvik [7]
I’m not to sure I was wondering the same thing
4 0
3 years ago
An indoor running track is 200 meters in length. During a 3,000-meter race, runners must complete 15 laps of the track. An elect
Vlad1618 [11]

The true statement based on the histogram is

There were no lap times between 35 and 36 seconds.

The correct option is (A).

<h3>What is Histogram?</h3>

A histogram is a graphical representation that organizes a group of data points into user-specified ranges.

Given:

indoor running track is 200 meters in length.

Also, a 3,000-meter race, runners must complete 15 laps of the track.

As, there no data for interval 35-36.

So, there were no lap times between 35 and 36 seconds.

Hence, The interval from 37 to 38 seconds saw the most lap times.

Learn more about histogram here:

brainly.com/question/16819077

#SPJ1

8 0
2 years ago
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