What is the slope of the line in the graph? HURRY!!!! I have one hour left !!!

Mathematics

2 answers:

erik [133]3 years ago

8 0

Answer:

Step-by-step explanation:

positive because as x increases, y increases

1 because for 1 increment of x there is 1 increment in y

equation is: y = x + 1

Margaret [11]3 years ago

8 0

Answer:

If you are going from 2,3 to 1,2 then it is -1,-1 but if you are going the other way then the ones are positive

Step-by-step explanation:

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Choose one of the factors of x^3 + 343

djyliett [7]

I've done this test before

The factor should be x+7 so, none of the above.

Hope I helped! ( Smiles )

4 0

3 years ago

The vertices of ΔMNO are M (1, 3), N (4, 9), and O (7, 3). The vertices of ΔPQR are P (3, 0), Q (4, 2), and R (5, 0). Which conc

vodka [1.7K]

Answer:

They are similar by the definition of similarity in terms of a dilation.

Step-by-step explanation:

Given:

The vertices of ΔMNO are M (1, 3), N (4, 9), and O (7, 3). The vertices of ΔPQR are P (3, 0), Q (4, 2), and R (5, 0).

To choose: the correct option

Solution:

According to distance formula distance between points $(x_1,y_1),(x_2,y_2)$ is given by $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

For ΔMNO,

$MN=\sqrt{(4-1)^2+(9-3)^2}=\sqrt{(3)^2+(6)^2}=\sqrt{45}\\NO=\sqrt{(7-4)^2+(3-9)^2}=\sqrt{(3)^2+(-6)^2}=\sqrt{45}\\\\MO=\sqrt{(7-1)^2+(3-3)^2}=\sqrt{(6)^2+(0)^2}=\sqrt{36}=6\\$

For ΔPQR,

$PQ=\sqrt{(4-3)^2+(2-0)^2}=\sqrt{(1)^2+(2)^2}=\sqrt{5}\\QR=\sqrt{(5-4)^2+(0-2)^2}=\sqrt{(1)^2+(-2)^2}=\sqrt{5}\\\\PR=\sqrt{(5-3)^2+(0-0)^2}=\sqrt{(2)^2+(0)^2}=2\\$