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yanalaym [24]
2 years ago
9

1. The graphs below represent functions defined by polynomials. For which function are the zeros of the

Mathematics
1 answer:
melamori03 [73]2 years ago
8 0

Answer:

the second graph (c)

Step-by-step explanation:

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One number is 9 less than a second number. Their sum is -27. What is the first number?
avanturin [10]

Answer:

x= first number y= second

x=2y+9 and x+y=129, these are the equations...solving gives x=89,y=40

Step-by-step explanation:

3 0
2 years ago
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Pizzeria Napoli sells a round pizza with diameter 16 inches and a square pizza with side length 15 inches. Which of the two shap
zavuch27 [327]

Answer: Square, 24 square inches

Step-by-step explanation:

Given

Diameter of round pizza d=16\ in.

Side of square pizza a=15\ in.

Area of circle \pi r^2

The area of a square is a^2

\therefore \text{Area of round Pizza}=\pi \times (\frac{16}{2})^2\\\Rightarrow A_1=\pi \times 8^2=201.088\ in.^2

The area of square pizza is

A_2=15^2=225\ in.^2

Clearly, the area of square pizza is more and the difference in their area is

\Rightarrow A_2-A_1=225-201.088=23.91\approx\ 24\ in.^2

6 0
2 years ago
you are to give a client one tablet labeled 0.15 mg and one labeled 0.025 mg. what is the total dosage of these two tablets
Ivenika [448]
Simply add the two dosages together, (0.15+0.025) and the answer is 0.175 :)
7 0
3 years ago
You roll a 4-sided die repeatedly. On your odd-numbered rolls (1st,3rd,5th, etc.) you are victorious if you get a 4. On your eve
Sunny_sXe [5.5K]

Answer:

E (Y) = 3

Step-by-step explanation:

If a 4-sided die is being rolled repeatedly; and the odd-numbered rolls (1st 3rd,5th, etc.)

The probability of odd number roll will be, p(T) = \frac{1}{2}

However, on your even-numbered rolls, you are victorious if you get a 3 or 4. Also, the  probability of even number roll, p(U) = \frac{1}{2}

In order to  calculate: E (Y); We can say Y to be the number of times you roll.

We know that;

E (Y) = E ( Y|T ) p(T) + E ( Y|U ) p(U)

Let us calculate E ( Y|T ) and E ( Y|U )

Y|T ≅ geometric = \frac{1}{4}

Y|U ≅ geometric = \frac{1}{2}

also; x ≅ geometric (p)

∴ E (x) = \frac{1}{p}

⇒ \frac{Y}{T} = 4 ; also \frac{Y}{U} = 2

E (Y) = 4 × \frac{1}{2} + 2 ×

        = 2+1

E (Y) = 3

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3 years ago
Answer for brainliest
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Answer:

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Step-by-step explanation:

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