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3 years ago

How to do long division for 2400 divided by 2.5.

Mathematics

1 answer:

defon3 years ago

3 0

Answer:

960

Step-by-step explanation:

1) multiply both numbers by 10 so you no longer have a decimal

2) use long division to divide the new numbers

3)24000÷25=960

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What’s this answer ? Please help!

tensa zangetsu [6.8K]

Answer:

Step-by-step explanation:

10 + 4 + 4 + 5 + 10 + 6 + 6 +2 + 2 or multiply them like this.

8 0

3 years ago

alexandra has a discount card that reduces the price of her grocery bill in a certain grocery store by 5% if c represents the co

BaLLatris [955]

I think the rest of the question is ( what is the price after the discount)
the new price will be = ( c - 0.05 *c )

6 0

3 years ago

A random sample of 10 parking meters in a resort community showed the following incomes for a day. Assume the incomes are normal

GenaCL600 [577]

Answer:

A 95% confidence interval for the true mean is [$3.39, $6.01].

Step-by-step explanation:

We are given that a random sample of 10 parking meters in a resort community showed the following incomes for a day;

Incomes (X): $3.60, $4.50, $2.80, $6.30, $2.60, $5.20, $6.75, $4.25, $8.00, $3.00.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean income = $\frac{\sum X}{n}$ = $4.70

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = $1.83

n = sample of parking meters = 10

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.262 < $t_9$ < 2.262) = 0.95 {As the critical value of t at 9 degrees of

freedom are -2.262 & 2.262 with P = 2.5%}

P(-2.262 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.262) = 0.95

P( $-2.262 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu$ < $2.262 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.262 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.262 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-2.262 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.262 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $4.70-2.262 \times {\frac{1.83}{\sqrt{10} } }$ , $4.70+ 2.262 \times {\frac{1.83}{\sqrt{10} } }$ ]

= [$3.39, $6.01]

Therefore, a 95% confidence interval for the true mean is [$3.39, $6.01].

The interpretation of the above result is that we are 95% confident that the true mean will lie between incomes of $3.39 and $6.01.

Also, the margin of error = $2.262 \times {\frac{s}{\sqrt{n} } }$

= $2.262 \times {\frac{1.83}{\sqrt{10} } }$ = 1.31

4 0

3 years ago

Express 13,040,000 in scientific notation

ser-zykov [4K]

$1.304 * 10^{7}$

8 0

3 years ago

Read 2 more answers

Jada has read 3/5 of a book. She has read 75 pages so far. How many pages are in the whole book?

saveliy_v [14]

Answer:

125 pages

Step-by-step explanation:

we can use a proportion

3/5=75/x

multiply cross so 75×5 and 3×X

375=3x

÷3. ÷3

x=125

check

75/125=simplified is 3/5

7 0

3 years ago