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3 years ago

Solve the subtraction equation two thirds minus four eighths equals blank. Use multiplication to create equivalent fractions.

Mathematics

2 answers:

valkas [14]3 years ago

7 0

Answer:

A. 4/24

Step-by-step explanation:

If you convert to a common fraction which is 24. Then you get 16/24 - 12/24= 4/24. And if you simplify you can get 1/6. Have a great day, let me know if correct, and hope this helps!

snow_tiger [21]3 years ago

4 0

The answer is 4/24 if I’m not mistaken btw have a good day

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mrs lemke has 10 2/3 ounces of fertilizer for her plants. She plans to use 3/4 ounce of fertilizer om each plant. After she put

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What we know:
Mrs Lemke has a total of 10 2/3 oz of fertilizer
3/4 oz fertilizer per plant

What we need to find is left over fertilizer after equally distributing as much 3/4 oz of fertilizer per plant.

10 2/3 oz must be divided into groups of 3/4 oz
Those groups will show how many plants can be fertilized with each receiving 3/4 oz of fertilizer and the remainder will be the left over fertilizer in ounces we need to find.

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3 years ago

4. A small high school holds its graduation ceremony in the gym. Because of seating constraints, students are limited to a maxim

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Answer:

(a) The mean and standard deviation of X is 2.6 and 1.2 respectively.

(b) The mean and standard deviation of T are 390 and 180 respectively.

(c) The distribution of T is N (390, 180²). The probability that all students’ requests can be accommodated is 0.7291.

Step-by-step explanation:

(a)

The random variable X is defined as the number of tickets requested by a randomly selected graduating student.

The probability distribution of the number of tickets wanted by the students for the graduation ceremony is as follows:

X P (X)

0 0.05

1 0.15

2 0.25

3 0.25

4 0.30

The formula to compute the mean is:

$\mu=\sum x\cdot P(X)$

Compute the mean number of tickets requested by a student as follows:

$\mu=\sum x\cdot P(X)\\=(0\times 0.05)+(1\times 0.15)+(2\times 0.25)+(3\times 0.25)+(4\times 0.30)\\=2.6$

The formula of standard deviation of the number of tickets requested by a student as follows:

$\sigma=\sqrt{E(X^{2})-\mu^{2}}$

Compute the standard deviation as follows:

$\sigma=\sqrt{E(X^{2})-\mu^{2}}\\=\sqrt{[(0^{2}\times 0.05)+(1^{2}\times 0.15)+(2^{2}\times 0.25)+(3^{2}\times 0.25)+(4^{2}\times 0.30)]-(2.6)^{2}}\\=\sqrt{1.44}\\=1.2$

Thus, the mean and standard deviation of X is 2.6 and 1.2 respectively.

(b)

The random variable T is defined as the total number of tickets requested by the 150 students graduating this year.

That is, T = 150 X

Compute the mean of T as follows:

$\mu=E(T)\\=E(150\cdot X)\\=150\times E(X)\\=150\times 2.6\\=390$

Compute the standard deviation of T as follows:

$\sigma=SD(T)\\=SD(150\cdot X)\\=\sqrt{V(150\cdot X)}\\=\sqrt{150^{2}}\times SD(X)\\=150\times 1.2\\=180$

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Here T = total number of seats requested.

Then, the mean of the distribution of the sum of values of X is given by,

$\mu_{T}=n\times \mu_{X}=390$

And the standard deviation of the distribution of the sum of values of X is given by,

$\sigma_{T}=n\times \sigma_{X}=180$

So, the distribution of T is N (390, 180²).

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$P(T$

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