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3 years ago

A linear equation that passes through (-6,-5) and parallel to 2x-3y=12

Mathematics

1 answer:

kumpel [21]3 years ago

6 0

Answer:

y= 2/3x-1

Step-by-step explanation:

The general formula for linear graph is y=mx + c. Let's convert the equation of the parallel line to be same as the formula:

2x-3y= 12

-3y= 12 -2x

y= 2/3x-4

Parallel lines won't ever be met because a couple of parallel lines will have the same slope(m). We know how much m is (m=2/3), then we just need to find c. We can do it by adding the value of the coordinate that the line pass (-6, -5). The calculation will be:

y=mx + c

-5= (2/3) (-6) + c

c= -5 +4

c= -1

The equation will be:

y=mx + c

y= 2/3x-1

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Answer : <em>Equation of line is</em> y=Equation of line is y= $\frac{2}{3}$ x+ $\frac{-5}{3}$

Step-by-step explanation:

Theory :

Equation of line is given as y = mx + c.

Where, m is slope and c is y intercepted.

Slope of given line : y = $\frac{2}{3}$ x+1 is m= $\frac{2}{3}$

We know that line : y = $\frac{2}{3}$ x+1 is parallel to equation of target line.

therefore, slope of target line will be $\frac{2}{3}$ .

we write equation of target line as y= $\frac{2}{3}$ x+c

Now, It is given that target line passes through point ( -5,-2)

hence, point ( -5,-2) satisfy the target line's equation.

we get,

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