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Alchen [17]
4 years ago
7

A linear equation that passes through (-6,-5) and parallel to 2x-3y=12

Mathematics
1 answer:
kumpel [21]4 years ago
6 0

Answer:

y= 2/3x-1

Step-by-step explanation:

The general formula for linear graph is y=mx + c. Let's convert the equation of the parallel line to be same as the formula:

2x-3y= 12

-3y= 12 -2x

y= 2/3x-4

Parallel lines won't ever be met because a couple of parallel lines will have the same slope(m). We know how much m is (m=2/3), then we just need to find c. We can do it by adding the value of the coordinate that the line pass (-6, -5). The calculation will be:

y=mx + c

-5= (2/3) (-6) + c

c= -5 +4

c= -1

The equation will be:

y=mx + c

y= 2/3x-1

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Let l(x) be the statement "x has an Internet connection" and C(x, y) be the statement "x and y have chatted over the Internet,"
Bas_tet [7]

The question is:

Let l(x) be the statement "x has an Internet connection" and C(x, y) be the statement "x and y have chatted over the Internet," where the domain for the variables x and y consists of all students in your class. Use quantifiers to express each of these statements.

a. Jerry does not have an Internet connection.

b. Rachel has not chatted over the Internet with Chelsea.

c. Jan and Sharon have never chatted over the Internet.

d. No one in the class has chatted with Bob.

e. Sanjay has chatted with everyone except Joseph.

f. Someone in your class does not have an Internet connection.

g. Not everyone in your class has an Internet connection.

h. Exactly one student in your class has an internet connection.

i. Everyone except one student in your class has an Internet connection.

j. Everyone in your class with an Internet connection has chatted over the Internet with at least one other student in your class.

k. Someone in your class has an Internet connection but has not chatted with anyone else in your class.

l. There are two students in your class who have not chatted with each other over the Internet.

m. There is a student in your class who has chatted with everyone in your class over the Internet.

n. There are at least two students in your class who have not chatted with the same person in your class.

o. There are two students in the class who between them have chatted with everyone else in the class.

Step-by-step explanation:

Note that: Because the arguments are variables, we write

Ix = I(x)

Cxy = C(x,y)

a. Jerry does not have an Internet connection.

~I(Jerry).

b. Rachel has not chatted over the internet with Chelsea.

~C(Rachel,Chelsea).

c. Jan and Sharon have never chatted over the internet.

~C(Jan,Sharon).

d. No one in the class has chatted with Bob.

~∃x C(x, Bob).

e. Sanjay has chatted with everyone except Joseph.

∀y (y ≠ Joseph → C(Sanjay, y)).

f. Someone in your class does not have an internet connection.

∃x ~Ix.

g. Not everyone in your class has an internet connection.

~∀x Ix.

h. Exactly one student in your class has an internet connection.

∃x (Ix ∧ ∀y (Iy → y = x)).

i. Everyone except one student in your class has an internet connection. This means exactly one student does not have a connection.

∃x (~Ix∧ ∀y (Iy → y = x)).

j. Everyone in your class with an internet connection has chatted over the internet with at least one other student in your class.

∀x (Ix → ∃y (Cxy ∧ x ≠ y)).

Assuming nobody can chat with him or herself, then

∀x (Ix → ∃y (Cxy))

k. Someone in your class has an internet connection but has not chatted with anyone else in your class.

∃x (Ix ∧ ∀y ~Cxy).

l. There are two students in your class who have not chatted with each other over the internet.

∃x ∃y (x ≠ y∧~Cxy).

m. There is a student in your class who has chatted with everyone in your class over the internet.

∃x ∀y Cxy.

n. There are at least two students in your class who have not chatted with the same person in your class. ∃x ∃y (x ≠ y ∧ ∃z (~Cxz ∧ ~Cyz)).

o. There are two students in the class who between them have chatted with everyone else in the class.

∃x ∃y (x ≠ y ∧ ∀z (Cxz ∨ Cyz)).

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Answer:

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Step-by-step explanation:

i took the test thingy and got it right;-;

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Answer:

3rd jump

Step-by-step explanation:

The distance jumped is given in the table attached. to get the jump that do not round up to 4.7 meters, we round each of the jump to one decimal place and then select the jump that does not round up to 4.7 meters.

Therefore rounding off gives:

1st jump: 4.746 meters = 4.7 meters to one decimal place

2nd jump: 4.680 meters = 4.7 meters to one decimal place

3rd jump: 4.647 meters = 4.6 meters to one decimal place (does not round to 4.7 meters)

4th jump = 4.733 meters = 4.7 meters to one decimal place

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Answer:

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Step-by-step explanation:

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4 years ago
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