A linear equation that passes through (-6,-5) and parallel to 2x-3y=12

Mathematics

1 answer:

kumpel [21]4 years ago

6 0

Answer:

y= 2/3x-1

Step-by-step explanation:

The general formula for linear graph is y=mx + c. Let's convert the equation of the parallel line to be same as the formula:

2x-3y= 12

-3y= 12 -2x

y= 2/3x-4

Parallel lines won't ever be met because a couple of parallel lines will have the same slope(m). We know how much m is (m=2/3), then we just need to find c. We can do it by adding the value of the coordinate that the line pass (-6, -5). The calculation will be:

y=mx + c

-5= (2/3) (-6) + c

c= -5 +4

c= -1

The equation will be:

y=mx + c

y= 2/3x-1

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6 Paul runs 1.5 km on the bearing 127°. a Draw a diagram of the situation. b How far east is Paul from his starting point? ( How

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By running in a bearing of 127°, Paul motion is in the south eastern direction.

Correct responses:

a. Please find attached the required diagram created with MS Visio

b. Paul's distance travelled east is approximately 11.98 km

Paul's distance travelled south is approximately 0.903 km

<h3>Method used for diagram and for the distance calculation</h3>

Given:

The distance Paul runs = 1.5 km

The bearing Paul is running = 127°

a. The bearing of path Paul runs, 127°, is the angle measured in the clockwise direction relative to the northern direction

Please find attached the diagram representing the situation, created with MS Visio.

b. Paul's distance travelled east relative to the starting point is given by the component of Paul's path in the x-axis direction which is found as follows;