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iragen [17]
3 years ago
15

Which one is exponential form? 3^2 3 + 3 3 x 3 3 x 3 x 3 :)

Mathematics
2 answers:
Over [174]3 years ago
8 0

Answer:

3^2 would be the correct answer.

luda_lava [24]3 years ago
8 0
3^2 is the correct answer
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The scatter plot shows the number of absences in a week for classes of different sizes. Trevor concluded that there is a positiv
QveST [7]
This is right the answer is A.
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3 years ago
Show how to use the distributive property to find 7 x 1214
Sophie [7]

Answer:8498

Step-by-step explanation:

(7*1000)+(7*200)+(7*10)+(7*4)

7000+1400+70+28

8498

8 0
3 years ago
I need help answer ASAP I’m confused
katrin [286]

Answer:

Step-by-step explanation:

You can plug in the 294 for A and solve

4 0
4 years ago
If p(x) = 2x2 – 4x and q(x) = x – 3, what is (p*q) (x)
jonny [76]
Hello:
(poq)(x) = p(q(x))=  p(x-3) = 2(x-3)²-4(x-3) = 2(x²-6x+9)-4(x-3)
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6 0
3 years ago
You are in charge of managing the advertising for a restaurant. You are able to buy up to 62 advertisements a month, and your da
erik [133]

Answer:

Greatest number of newspaper ads = 59

Greatest number of television ads = 23

Step-by-step explanation:

It is given that we should buy at least 5 newspapers for every 3 television ads.

So, after purchasing 3 television ads, we can buy any number of television ads but the number should be greater than 5.

Since, the maximum is 62, we can buy 59 newspaper ads. (Note that we have already bought 3 television ads).

For every 3 television ads, we should buy 5 newspaper ads. So,

For the purchase of 3 television ads, we should buy the minimum of 5 newspaper ads.

For the purchase of 2(3) television ads, we should buy the minimum of 2(5) newspaper ads.

For the purchase of 3(3) television ads, we should buy the minimum of 3(5) newspaper ads.

...

...

For the purchase of 7(3) = 21 television ads, we should buy the minimum of 7(5) = 35 newspaper ads.

So, totally 21+35 = 56 ads.

For the remaining 6 ads, if we buy 3 television ads, we should buy 5 newspaper ads.

So, we can buy 2 television ads and 4 newspaper ads.

Hence, we can buy the maximum of 21+2 = 23 television ads.

7 0
3 years ago
Read 2 more answers
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