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4 years ago

4(x − 4) + 2(3x2 + 3x − 20)

Mathematics

1 answer:

Feliz [49]4 years ago

7 0

Answer:

$10x-56 + 6x^{2}$

Step-by-step explanation:

Step 1: $4x-16+2(3x^{2} +3x-20)$

Step 2: $4x-16+6x^{2} +6x-40$

Step 3: $(4x+6x) + (-16-40) +6x^{2}$

Step 4: $10x - 56 + 6x^{2}$

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R/5 - 6 = -1 r=1 r=5 r=10 r=25

posledela

R = 30 because r = 1,5,10,25
30/5+1=7
6+1=7

5 0

3 years ago

The sum of two numbers is 35. One number is 7 less than the other. Find the numbers.

Sladkaya [172]

Answer:

14+21

Step-by-step explanation:

because, 14+21 =35

21 is 7 more bigger than 14

5 0

3 years ago

Use a net to find the total surface of the prism.

elixir [45]

Answer:

6682.5cm

Step-by-step explanation:

29+6.5=35.5+19=54.5+1,726=1,780.5+1121=2901.5+2671=5572.5+1110=6682.5

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3 years ago

Please help!! Find the number if intercepts of the graph of the function f(x)=x^2-2x+5

hodyreva [135]

Answer: X does not intercept (none)

Y=(0,5)

Step-by-step explanation:

7 0

3 years ago

Please help FAST I need the answer along with you explaining the steps so I can get it thanks! I’ll give Brainlist also!

kupik [55]

Answer:

The equation of required line is: $\mathbf{5x-8y+34=0}$

Step-by-step explanation:

We need to write equation in the form Ax+By+C=0 of the line parallel to $5x-8y+12=0$ and through the point (-2,3)

First we need to find slope and y-intercept of the required line.

Using equation of line $5x-8y+12=0$ to find slope.

Since the given line and required lines are parallel there slope is same.

Writing equation in slope intercept form: $y=mx+b$ where m is slope.

$5x-8y+12=0 \\-8y=-5x-12\\\frac{-8y}{-8y}=\frac{-5x}{-8}-\frac{12}{-8}\\y=\frac{5}{8}x+\frac{3}{4}$

So, the slope m = 5/8

The slope of required line is $m=\frac{5}{8}$

Now finding y-intercept using slope $m=\frac{5}{8}$ and point(-2,3)

$y=mx+b\\3=\frac{5}{8}(-2)+b\\3=\frac{-5}{4}+b\\b=3+\frac{5}{4}\\b=\frac{3*4+5}{4}\\b=\frac{12+5}{4}\\b=\frac{17}{4}$

So, the equation of required line having slope $m=\frac{5}{8}$ and y-intercept $b=\frac{17}{4}$

$y=mx+b\\y=\frac{5}{8}x+\frac{17}{4}\\y=\frac{5x+17*2}{8}\\y= \frac{5x+34}{8} \\8y=5x+34\\5x-8y+34=0$

So, The equation of required line is: $\mathbf{5x-8y+34=0}$

3 0

3 years ago