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2 years ago

V = BH - 5 How do I solve for b in this equation

Mathematics

1 answer:

Zolol [24]2 years ago

6 0

Answer:

$B=\frac{V+5}{H}$

Step-by-step explanation:

Add 5 to both sides:

V+5=BH

Divide both sides by H:

$B=\frac{V+5}{H}$

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Determine whether y varies directly with x. If so, find the constant of variation k.

kumpel [21]

Direct variation is y=kx, inverse variation is y=k/x....

-5y=-2x divide both sides by -5

y=2.5x

So this is a direct variation with a constant of 2.5

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3 years ago

Which equation is y = 2x2 – 8x + 9 rewritten in vertex form?

pishuonlain [190]

we have

$y=2x^{2} -8x+9$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-9=2x^{2} -8x$

Factor the leading coefficient

$y-9=2(x^{2} -4x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-9+8=2(x^{2} -4x+4)$

$y-1=2(x^{2} -4x+4)$

Rewrite as perfect squares

$y-1=2(x-2)^{2}$

$y=2(x-2)^{2} +1$ -----> equation in vertex form

therefore

the answer is the option C

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Answer:

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I dont need it anymore

vova2212 [387]

Answer:

I'm sorry but what is the question?

Step-by-step explanation:

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