Answer:
The store should use 112.5 pounds of Brazilian coffee and 37.5 pounds of Colombian cofee.
Step-by-step explanation:
Let "b" be the amount of Brazilian coffee, in pounds, required for the blend and "c" the amount of Colombian coffee required, in pounds.
Since there are two unknown variables a two-equation system is needed to solve the problem, we can set up one equation for weight and another for price as follows:

Solve for "c" by multiplying the first equation by -10 and adding it to the second one:

Now, solve for b by replacing the value obtained into the first equation

The store should use 112.5 pounds of Brazilian coffee and 37.5 pounds of Colombian cofee.
Answer:
y=3.5
Step-by-step explanation:
<u>7</u><u>y</u><u>-</u><u>4</u><u>.</u><u>6</u><u>-</u><u>6</u><u>y</u>
<u>4</u><u>.</u><u>5</u><u>=</u><u>7</u><u>y</u><u>+</u><u>6</u><u>y</u>
<u>4</u><u>.</u><u>5</u><u>=</u><u>1</u><u>3</u>y
4.5. 4.5
y=3.5
Answer:
Mean= 242.5 pounds
Median= 236 pounds
Mode= 208 and 278 pounds
Range=117 pounds
Mid-range= 58.5 pounds
B. The results are likely to be representative because a championship team is most likely representative of the entire league.
Step-by-step explanation:
278 303 186 292 276 205 208 236 278 198 208
Arranged in ascending order is
186 198 205 208 208 236 276 278 278 292 303
Mean = (186 +198+ 205+ 208 +208 +236 + 276+ 278 +278+ 292 +303)/11
Mean =2668/11
Mean= 242.5 pounds
Median = the middle number
Median= 236 pounds
Mode = highest occuring number(s)
Mode= 208 and 278 pounds
Range= highest number- smallest number
Range=303-186
Range=117 pounds
Mid-range= range/2
Mid-range= 117/2
Mid-range= 58.5 pounds
6.3*10^17 is correct hope this helps