Help pleaseeeeeeeeeee

Mathematics

2 answers:

Andrews [41]3 years ago

7 0

Answer:

I don't help ppl who just takes points from ppl with out helping :) Look at the past answers from her.

Step-by-step explanation:

Katyanochek1 [597]3 years ago

3 0

Answer:

4, 7, 9, 12, 18, 32

Step-by-step explanation:

The sign shows that any number that is equal to, or more than, 36 is a valid answer. It can't be 3 because 3 x 9 is 27, and 27 is less than 36, so that wouldn't be true. 4 x 9 is 36, and 36 = 36, so that would be true, and obvoiusly all the other numbers that are over 4, when multiplied by 9, will equal more than 36, so they are all correct, except for the 3 and none answers. I hope this helps you out :)

You might be interested in

How to find variables of these #2 & #3

Lubov Fominskaja [6]

So... hmmm if you check the first picture below, for 2)

we could use the proportions of those small, medium and large similar triangles like $\bf \cfrac{small}{large}\qquad \cfrac{x}{12}=\cfrac{6}{x}\impliedby \textit{solve for "x"}
\\\\\\
\cfrac{small}{large}\qquad \cfrac{z}{18}=\cfrac{6}{z}\impliedby \textit{solve for "z"}
\\\\\\
\cfrac{large}{medium}\qquad \cfrac{y}{12}=\cfrac{18}{y}\impliedby \textit{solve for "y"}$

now.. for 3) will be the second picture below

$\bf \cfrac{large}{medium}\qquad \cfrac{x+10}{2\sqrt{30}}=\cfrac{2\sqrt{30}}{10}\impliedby \textit{solve for "x"}
\\\\\\
\textit{now, because you already know what "x" is, we can use it below}
\\\\\\
\cfrac{large}{small}\qquad \cfrac{z}{x}=\cfrac{x+10}{z}\impliedby \textit{solve for "z"}
\\\\\\
\textit{and let us use "x" again below}
\\\\\\
\cfrac{small}{medium}\qquad \cfrac{y}{10}=\cfrac{x}{y}\impliedby \textit{solve for "y"}$

8 0

3 years ago

arron takes his dog for a walk afer school, he walks 5 blocks east and then 4 blocks north. if he was able to take a direct rout

nlexa [21]

Hi!

We are given the information found in the picture below.

Note: The directions aren't correct, but the triangle works for this problem.

The "direct path" is the hypotenuse of this triangle.

To find this, we use the Pythagorean Theorem, where $a$ and $b$ are 2 legs of the triangle, and $c$ is the hypotenuse, aka the longest side of any triangle: