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KiRa [710]
3 years ago
15

Help pleaseeeeeeeeeee

Mathematics
2 answers:
Andrews [41]3 years ago
7 0

Answer:

I don't help ppl who just takes points from ppl with out helping :) Look at the past answers from her.

Step-by-step explanation:

Katyanochek1 [597]3 years ago
3 0

Answer:

4, 7, 9, 12, 18, 32

Step-by-step explanation:

The sign shows that any number that is equal to, or more than, 36 is a valid answer. It can't be 3 because 3 x 9 is 27, and 27 is less than 36, so that wouldn't be true. 4 x 9 is 36, and 36 = 36, so that would be true, and obvoiusly all the other numbers that are over 4, when multiplied by 9, will equal more than 36, so they are all correct, except for the 3 and none answers. I hope this helps you out :)

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If x=1,y=3,z=4 evaluate x^2+y^2+z^2-3yz^2
Travka [436]
<h3>✽ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

➷ Just substitute the values in:

(1)^2 + (3)^2 + (4)^2 - 3(3)(4)^2

Simplify:

(1 + 9 + 16) - 144

Simplify further to get the answer:

answer = -118

<h3><u>✽</u></h3>

➶ Hope This Helps You

➶ Good Luck

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

7 0
3 years ago
Solve the following <br><br> 4x-1/2=x+7
kipiarov [429]

Answer: x= 5/2

Step-by-step explanation::)

7 0
2 years ago
The dishes have been sorted into cups and plates. The number of plates is four less than two times the number of cups. The dishe
Nady [450]

Answer:

The number of cups = 8 ....

Step-by-step explanation:

Let x be the number of cups

Let y be the number of plates

According to the given statement:

y=2x-4   This is equation 1

Now,

60% = 0.60

y=0.60(x+y)    This is equation 2

Now substitute equation 1 in equation 2.

y=0.60(x+y)

2x-4=0.60(x+2x-4)

2x-4=0.6x+1.2x-2.4

Solve the like terms:

2x-4=1.8x-2.4

2x-1.8x=4-2.4

0.2x=1.6

x=1.6/0.2

x= 8 cups

Therefore the number of cups = 8 ....

7 0
3 years ago
Enter 52.16 in expanded form.
ivolga24 [154]

Answer:

50 + 2 + 0.1 + 0.06

5 0
3 years ago
Read 2 more answers
Calculus question?
Ann [662]
Remark
If you don't start exactly the right way, you can get into all kinds of trouble. This is just one of those cases. I think the best way to start is to divide both terms by x^(1/2)

Step One
Divide both terms in the numerator by x^(1/2)
y= 6x^(1/2) + 3x^(5/2 - 1/2)
y =6x^(1/2) + 3x^(4/2)
y = 6x^(1/2) + 3x^2   Now differentiate that. It should be much easier.

Step Two
Differentiate the y in the last step.
y' = 6(1/2) x^(- 1/2) + 3*2 x^(2 - 1)
y' = 3x^(-1/2) + 6x  I wonder if there's anything else you can do to this. If there is, I don't see it.

I suppose this is possible.
y' = 3/x^(1/2) + 6x

y' = \frac{3 + 6x^{3/2}}{x^{1/2}}

Frankly I like the first answer better, but you have a choice of both.
5 0
3 years ago
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