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kirza4 [7]
3 years ago
6

A fair, twenty-faced die has $19$ of its faces numbered from $1$ through $19$ and has one blank face. another fair, twenty-faced

die has $19$ of its faces numbered from $1$ through $8$ and $10$ through $20$ and has one blank face. when the two dice are rolled, what is the probability that the sum of the two numbers facing up will be $24?$ express your answer as a common fraction.
Mathematics
1 answer:
lawyer [7]3 years ago
8 0
Represent 24 as a sum of two numbers, first number from first die and second number from second die.
24=19+5=18+6=17+7=16+8=14+10=13+11=12+12=11+13=10+14=9+15=8+16=7+17=6+18=5+19=4+20 (the sums 15+9 and 20+4 are absent, because there aren't numbers: 20 on the first die and number 9 on the second die). Totally, you receive 15 different representations of 24.
<span>The probability that the sum of the two numbers facing up will be 24 is
</span><span>
</span><span>P= \frac{15}{20\cdot 20} = \frac{3}{80} (here 20\cdot 20 means that you have 20 possibilities to roll first number or blank face on the first die and 20 possibilities to roll number or blank face on the second die).
</span>


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Answer:

60

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Multiples of 20:

20, 40, <u>60</u>, 80, 100

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30, <u>60</u>, 90, 120

so the LCM(20, 30)=60

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4 0
3 years ago
Estimate the square root to the nearest integer and tenth square root of 8
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√

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Explanation:

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(

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=

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⎧

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8 0
3 years ago
A rectangle has a length of 72 cm and a width of 56 cm. The other rectangle has the same area as this one, but its width is 21cm
andrew-mc [135]

Answer: I think it’s 4032

Step-by-step explanation:

8 0
3 years ago
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liraira [26]

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Define variables:

Let x= cost of 1 adult tickets , y= cost of 1 child tickets.

Form linear equations:

5x+3y = 210      (i)

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Eliminate (iii) from (iv)

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Hence, Cost of adult ticket = $ 30 and Cost of child ticket = $20

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