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Flura [38]
3 years ago
9

10. How many solutions does this system of equations have? Explain how you know.

Mathematics
1 answer:
Shkiper50 [21]3 years ago
5 0
2 solutions of this system of equation
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It would be (3,10) because it is much bigger then the others
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Use the drop-down menus to choose steps in order to correctly solve<br> 5m – 8 = 3m + 8 for m.
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5m - 3m = 8 + 8
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What is the inverse of y = 3x + 9? A. y= 1/3x - 3 B. y = 1/3x + 9 C. y = -1/3x - 3 D. y = 9x + 3
Aneli [31]

Answer:

1/3x - 3

Step-by-step explanation:

To find the inverse, we exchange x and y and then solve for y

y =3x+9

Exchange x and y

x = 3y+9

Then solve for y

Subtract 9 from each side

x-9 =3y+9-9

x-9 = 3y

Divide by 3

1/3(x-9) = 3y/3

1/3(x-9) = y

Distribute

1/3x-3 = y

The inverse is 1/3 x -3

6 0
3 years ago
Someone please please help. I have to submit this is about 15 minutes​
Angelina_Jolie [31]

Answer:

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Step-by-step explanation:

5 0
2 years ago
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8.36 Football and Brain Size: Randomization Test Exercise 8.35 describes a study examining hippocampus volume in the brain betwe
erma4kov [3.2K]

Answer:

Since the calculated F=  2.8657 does not lie in the critical region  F (2,2)≥ 19 we conclude that there no difference between the means.

Since the calculated F=  205.0819  lies in the critical region F(1,2) ≥ 18.51  we conclude that there is a difference between the standard deviations of the three groups.

The F- statistic for the observed data is 0.101  as calculated by F- test in excel.

Step-by-step explanation:

To conduct an ANOVA randomization test we perform anova without replication in excel.

The data for the test is

   

                            Mean    Standard Deviation Sample Size

Never

Played Football 7602.5          1074                   25

FB with no History   6459.2         779.9                  25

<u>FB with Concussion 5734.6       593.4                   25 </u>

<u>Total                 6598.8      1133.5                  75 </u>

<u />

Anova: Two-Factor Without Replication    

   

SUMMARY Count Sum Average Variance

Row 1 2 8676.5 4338.25 21310656.13

Row 2 2 7239.1 3619.55 16127224.25

Row 3 2 6328 3164 13215968.72

   

Column 1 3 19796.3 6598.766667 886871.7433

Column 2 3 2447.3 815.7666667 58708.90333

<u>ANOVA Table </u>  

Source           Sum of     Degrees     Mean

of Variation      Square    of freedom  Squares

<u>                             SS     df          MS              F P-value </u>

B/w Rows 1401945.703 2 700972.8517 2.8657 0.259

B/w Col      50164633.5 1 50164633.5 205.0819  0.00484

<u>Error     489215.59         2 244607.795                           </u>

Total 52055794.79 5    

Set up the null and alternate hypotheses :

H0 ; there's no difference between the means and

there's no difference between the standard deviations

against the claim

Ha: there's a difference between the means and

there's  a difference between the standard deviations

The significance level is chosen at 0.05

The test statistics to use are

F1= estimated variance from Between Means/  estimated variance from Error SS

F1= s1²/s3²

F1= estimated variance from Between Standard Deviations /  estimated variance from Error SS

F2- s2²/s3²

with υ1= (2,2)  and υ2(1,2) degrees of freedom.

The critical regions for F (2,2)≥ 19 for 0.05 significance level

and F(1,2) ≥ 18.51  for 0.05 significance level

Since the calculated F=  2.8657 does not lie in the critical region  F (2,2)≥ 19 we conclude that there no difference between the means.

Since the calculated F=  205.0819  lies in the critical region F(1,2) ≥ 18.51  we conclude that there is a difference between the standard deviations of the three groups.

The F- statistic for the observed data is 0.101  as calculated by F- test in excel.

7 0
2 years ago
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