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aleksandr82 [10.1K]
3 years ago
11

Which ordered pair is a solution of the equation? 3х + Зу = - x + 5y

Mathematics
1 answer:
IRISSAK [1]3 years ago
7 0

Answer:

(0,0)

Step-by-step explanation:

if you put the two equations together on a graph, the point where they meet is (0,0)

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Can you answer this one for my plz I need before Monday ty
ira [324]
Since you need the vertex, and knowing the vertex will tell you the axis of symmetry, it is convenient to put the equation in vertex form.
.. -x^2 -4x +1
.. = -(x^2 +4x) +1
.. = -(x^2 +4x +(4/2)^2) +1 -(-(4/2)^2) . . . . complete the square
.. = -(x +2)^2 +5

The vertex is (-2, 5).
The axis of symmetry is x = -2.

7 0
3 years ago
A tank contains 1000L of pure water. Brine that contains 0.02kg of salt per liter enters the tank at a rate of 5L/min. Also, bri
tankabanditka [31]

Answer:

51.877 kg

Step-by-step explanation:

a

See attachment for calculations

b

The amount of salt in the tank after 4 hours is gotten by simply replacing t in the equation from a, with 4 hours. Since the t gotten in a above is in minutes, we'd convert hours to minute as well. If we do that, we have

t = 4 hours = 4 * 60 minutes = 240 minutes

y = 160/3 (1 - e^((-3 * 240)/200))

y = 160/3 (1 - e^(-720/200))

y = 160/3 (1 - 0.0273)

y = 160/3 (0.9727)

y = 51.877 kg

Therefore, the amount of salt in the tank after 4 hours is 51.877 kg

3 0
3 years ago
On the first day that tickets to the school play were sold, 100 tickets were sold for $230. Regular tickets cost $3 and student
algol [13]
30 of the $3 tickets were sold
70 of the $2 tickets were sold.

(3*30) + (2*70) = 230
6 0
3 years ago
Read 2 more answers
What is the Y intercept of the function Y=(x+2) (x-4)
trasher [3.6K]
Answer:
Y=x^2-2x-8,x , x=r
5 0
3 years ago
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A ship leaves port at 1:00 P.M. and travels S35°E at the rate of 27 mi/hr. Another ship leaves the same port at 1:30 P.M. and tr
Len [333]

To solve this problem you must apply the proccedure shown below:

1. You must apply the Law of Cosines, as you can see in the figure attached. Then:

- The first ship travels at 27 mi/hr in for two hours. Therefore, the side a is:

a=(27 mi/hr)(2 hr)=54mi

- The second ship travels at 18 mi/hr for 1.5 hours. Therefore, the side b is:

b=(18mi/hr)(1.5hr)=27mi

- Now, you can calculate c:

c=\sqrt{54^{2}+27^{2}-2(54)(27)Cos(55)}=44 mi

The answer is: 44 miles

8 0
3 years ago
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