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Gwar [14]
3 years ago
11

A student wondered if more than​ 10% of students enrolled in an introductory Chemistry class dropped before the midterm. He noti

ced that 2 out of 15 of his friends in the class dropped before the midterm. Based on his​ sample, he performed a hypothesis test. Is the hypothesis test a​ one-tailed or​ two-tailed test?
Choose the correct answer below.
A.It is a​ two-tailed test since the null hypothesis states that the parameter is not equal to the hypothesized valued.
B.It is a​ two-tailed test since the alternative hypothesis states that the parameter is not equal to the hypothesized value.
C.It is a​ one-tailed test since the alternative hypothesis states that the parameter is greater than the hypothesized value.
D.It is a​ one-tailed test since the alternative hypothesis states that the parameter is not equal to the hypothesized value.
E.It is a​ two-tailed test since the alternative hypothesis states that the parameter is greater than they hypothesized value.
Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
3 0

Answer:

C.It is a​ one-tailed test since the alternative hypothesis states that the parameter is greater than the hypothesized value.

Step-by-step explanation:

Let p be the percentage of students enrolled in an introductory Chemistry class dropped before the midterm. Then null and alternative hypotheses are:

H_{0}: p=10%

H_{a}: p>10%

The alternative hypothesis states that the parameter is greater than the hypothesized value.

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The first term of an arithmetic sequence is 1 and the sum of the first four terms is 100. Find the first four terms ​
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Answer:

1, 17, 33, 49

Step-by-step explanation:

given the first term is 1 then the next 3 terms are

1 + d, 1 + 2d, 1 + 3d ( d is the common difference )

the sum of the first 4 terms is 100 , then

1 + 1 + d + 1 + 2d + 1 + 3d = 100 , that is

4 + 6d = 100 ( subtract 4 from both sides )

6d = 96 ( divide both sides by 6 )

d = 16

1 + d = 1 + 16 = 17

1 + 2d = 1 + 2(16) = 1 + 32 = 33

1 + 3d = 1 + 3(16) = 1 + 48 = 49

the first 4 terms are

1, 17, 33, 49

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