The correct question is
<span>how many times as large is the approximate radius of a mercury atom, 1.50*10^-11 meter, as the approximate radius of a hydrogen atom, 2.5*10^-11
</span>
Since both are conveniently --------> *10^-11
<span>we can just divide 2.5 by 1.5
</span>2.5/1.5-------> 1.6666
<span>So a hydrogen atom is 1.67 times larger than a mercury atom</span>
Answer:
C(5,-9) and r=8.
Step-by-step explanation:
C(p, q) - center
r=radius
k:x^2 +y^2 +dx+ey+f=0
x^2+y^2 - 10x+18y+42=0
d=-10, e=18, f=42
p=-d/2=-(-10)/2=10/2=5
q=-e/2=-18/2=-9
r^2 =p^2+q^2-f
r^2 =5^2 +(-9)^2 - 42
r^2=25+81-42
r^2 =106-42
r^2 =64
r=sqrt(64)
r=8
C(p,q)=C(5,-9) r=8
Answer:
Yes
Step-by-step explanation:
Yes.
Let's first start with even numbers. (N - even number)
Any even number squared, is an even number. Then, we add that squared even number to another even number which would give us an even number.
Now, let's see odd numbers.
Any odd number squared would be an odd number. When you add "N", it would be adding an odd number to an odd number, which gives you an even number.
OR
We can start by factoring the expression:

This is essentially multiplying two consecutive numbers, which in turn means that one number has to be even, and one has to be odd. An odd number multiplied by an even number will always be even.
For this case we have that by definition, the density is given by:

Where:
M: It is the mass of the diamond
V: It is the volume of the diamond
According to the data of the statement we have:

So the volume is:

Thus, the volume of the diamond is approximately 
Answer:

Answer: Answer and explanation in pic
Step-by-step explanation: