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Makovka662 [10]
3 years ago
7

If the mean of the data set is 41 attendees find the number of attendees at Harry’s hoedown

Mathematics
1 answer:
DaniilM [7]3 years ago
7 0

Answer:

42

Step-by-step explanation:

Add up the values in your data set and divide by the number of terms in the data. Let x represent attendees at Harry's Hoedown, then. Mean = 41 = 123 = 48 + 33 + x. 123 = 81 + x. 42 = x. Answer: 42

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Write a C program to compute Matrix Multiplication of two matrices. Use one dimensional array to store each matrix, where each row is stored after another. Hence, the size of the array will be a product of number of rows times number of columns of that matrix. Get number of row and column from user and use variable length array to initialize the size of the two matrices as well as the resultant matrix. Check whether the two matrices can be multiplied or not. Write a getMatrix() function to generate the array elements randomly. Write a printMatrix() function to print the 1D array elements in 2D Matrix format. Also, write another function product(), which multiplies the two matrices and stores in the resultant matrix. With SEED 5, the following output is generated.

Sample Output

Enter the rows and columns of Matrix A with space in between: 3 5

Enter the rows and columns of Matrix B with space in between: 5 4

Matrix A:

    8     6     4     1     6

    2     9     7     7     5

    1     3     1     1     2

Matrix B:

    9     5     4     5

    9     9     8     1

    4     4     3     5


    2     6     2     1

    4     5     2     4

Product AxB:

168   146   106    91

161   186   125    81

50    52    37    22

In conclusion, the answer is 5x1

Please give Brainliest answer thanks! :)

6 0
3 years ago
Read 2 more answers
Which equation has a graph that passes through the points at (0,5) and (-3,-4)?
Roman55 [17]

Answer:

y = 3x + 5

Step-by-step explanation:

We are asked the equation of the graph which passes through the points at (0,5) and (-3,-4).  

Now, we know that the equation of a straight line passing through the points (x_{1},y_{1}) and (x_{2},y_{2}) is given by

\frac{y - y_{1}}{y_{1} - y_{2}} = \frac{x - x_{1}}{x_{1} - x_{2}}.

So, in our case (x_{1},y_{1}) ≡ (0,5) and (x_{2},y_{2}) ≡ (-3,-4)

Therefore, the equation of the straight line will be  

\frac{y - 5}{5 - (- 4)} = \frac{x - 0}{0 - (- 3)}

⇒ y - 5 = \frac{9}{3}x

⇒y = 3x + 5 (Answer)

4 0
3 years ago
A) Find a recurrence relation for the number of bit strings of length n that contain a pair of consecutive 0s.
Fed [463]

Answer:

A) a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}

B) a_{0} = a_{1} = 0

C)   for n = 2

  a_{2} = 1

for n = 3

 a_{3} = 3

for n = 4

a_{4} = 8

for n = 5

a_{5} = 19

Step-by-step explanation:

A) A recurrence relation for the number of bit strings of length n that contain a  pair of consecutive Os can be represented below

if a string (n ) ends with 00 for n-2 positions there are a pair of  consecutive Os therefore there will be : 2^{n-2} strings

therefore for n ≥ 2

The recurrence relation for the number of bit strings of length 'n' that contains consecutive Os

a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}

b ) The initial conditions

The initial conditions are : a_{0} = a_{1} = 0

C) The number of bit strings of length seven containing two consecutive 0s

here we apply the re occurrence relation and the initial conditions

a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}

for n = 2

  a_{2} = 1

for n = 3

 a_{3} = 3

for n = 4

a_{4} = 8

for n = 5

a_{5} = 19

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3 years ago
It has to do with slopes or something ​
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2 years ago
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Answer:

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3 years ago
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