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likoan [24]
3 years ago
11

If y varies inversely as the square root of x, what is the constant of proportionality if y = 16 when x = 4?

Mathematics
1 answer:
krek1111 [17]3 years ago
5 0
The answer is D.64

Explain i have the test myself
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Find the domain of the function y = 3 tan(23x)
solmaris [256]

Answer:

\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

In other words, the x in f(x) = 3\, \tan(23\, x) could be any real number as long as x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) for all integer k (including negative integers.)

Step-by-step explanation:

The tangent function y = \tan(x) has a real value for real inputs x as long as the input x \ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

Hence, the domain of the original tangent function is \mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

On the other hand, in the function f(x) = 3\, \tan(23\, x), the input to the tangent function is replaced with (23\, x).

The transformed tangent function \tan(23\, x) would have a real value as long as its input (23\, x) ensures that 23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

In other words, \tan(23\, x) would have a real value as long as x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right).

Accordingly, the domain of f(x) = 3\, \tan(23\, x) would be \mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

4 0
2 years ago
-8x+7+6=-3<br> Answers <br> No solution<br> -1 <br> 4<br> 2
Natali5045456 [20]

Answer:

It's 2

Step-by-step explanation:

Because

-16/-8=2

7 0
3 years ago
Translate to an algebraic expression: 15 less than six times a number, y.
Natalija [7]

Answer:

4

Step-by-step explanation:

6 0
3 years ago
Use pi=3<br> Calculate the area of a circle with a diameter of 10cm
GalinKa [24]
Area of a circle is 75 cm².

Area of a circle is computed by multiplying pi to the square of the radius.

A = πr²

diameter = 10 cm
radius = d/2 = 10/2 = 5 cm
pi = 3

A = 3(5cm²)
A = 3(25cm²)
A = 75 cm²
7 0
3 years ago
2 3/4 x 8 = blank/4 x 8/1
Alex

Answer: 11

Step-by-step explanation:

2 3/4 × 8 = p/4 × 8/1

Let p be the missing number

Convert the mixed fraction 2 3/4 to proper fraction, multiply 4 x 2, then add 3= 11/4

11/4 × 8 = p/4 ×8

p= 11

I hope this helps.

5 0
3 years ago
Read 2 more answers
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