Simplify -15.4/-4……………………. −3.9 3.9 −4.9 4.9

Can someone plz help me solve this problem I need help plz someone help me!

cestrela7 [59]

Answer: 25 < P < 36

15/4 < w < 26/4

35/4 < L < 46/4

Step-by-step explanation:

Perimeter is BETWEEN 25 and 36

25 < P < 36

Graph: O--------------O

25 36

Perimeter = 2L + 2w ; substitute L = w + 5

25 < 2(w + 5) + 2w < 36

25 < 2w + 10 + 2w < 36

25 < 4w + 10 < 36

15 < 4w < 26

$\dfrac{15}{4}$ < w < $\dfrac{26}{4}$

$3\dfrac{3}{4}$ < w < $6\dfrac{1}{2}$

Graph: O------------------------O

$3\dfrac{3}{4}$ $6\dfrac{1}{2}$

Perimeter = 2L + 2w ; L = w + 5 --> w = L - 5

25 < 2L + 2(L - 5) < 36

25 < 2L + 2L - 10 < 36

25 < 4L - 10 < 36

35 < 4L < 46

$\dfrac{35}{4}$ < L < $\dfrac{46}{4}$

$8\dfrac{3}{4}$ < L < $11\dfrac{1}{2}$

Graph: O------------------------O

$8\dfrac{3}{4}$ $11\dfrac{1}{2}$

Note: Make sure you use OPEN dots when graphing.

5 0

4 years ago

What is 6.39 rounded to the nearest tenths?

posledela

6.4 is the answer to your question

4 0

3 years ago

Read 2 more answers

List all of the possible rational roots.

tatuchka [14]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Kubin Company’s relevant range of production is 25,000 to 33,500 units. When it produces and sells 29,250 units, its average cos

Keith_Richards [23]

Answer:

the 2nd option is correct

Step-by-step explanation:

8 0

3 years ago

Find the equation for the circle with a diameter whose endpoints are (3,-1) and (-2,-1)

cricket20 [7]

Answer:

The equation for the circle is: $(x-\frac{1}{2} )^2 + y^2 = (\frac{5}{2} )^2$

Step-by-step explanation:

Here, let us assume the two end points of the diameter are:

P (3,-1) and Q (-2,-1)

Now, as we knew diameter is the chord that passer through the center of the circle.

⇒ Mid point of DIAMETER = Center coordinates of the Circle

Let us assume O(x,y) is the center of the line segment PQ.

So, by MID POINT FORMULA:

$(x,y)= (\frac{3 -2}{2} , \frac{-1-1}{2} ) =( \frac{1}{2},\frac{-2}{2}) \\\implies (x,y) =( 0.5 , -1)$

⇒ The center coordinates of the circle = O(0.5,-1) ...... (1)

Now, RADIUS = Half of DIAMETER

Using DISTANCE FORMULA:

$PQ = \sqrt{(3-(-2))^2 + (-1 - (-1))^2} = \sqrt{(5)^2 + 0} = 5$

So, Radius = 5/2 = 2.5 units

Now, the equation of circle with radius r and center coordinate ( h,k) is given as: $(x-h)^2 + (y-k)^2 = r^2$

Substitute r = 2.5 and (h,k) = (0.5,0) we get:

$(x-0.5)^2 + (y-0)^2 = (2.5)^2\\\implies (x-\frac{1}{2} )^2 + y^2 = (\frac{5}{2} )^2$

Hence the equation for the circle is: $(x-\frac{1}{2} )^2 + y^2 = (\frac{5}{2} )^2$

5 0

4 years ago