Answer:

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

And we can solve for
and solving we got:

And from the previous result we got:

And solving we got:

And then we can find the mean with this formula:

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0
Step-by-step explanation:
For this case we know that the currently mean is 2.8 and is given by:

Where
represent the number of credits and
the grade for each subject. From this case we can find the following sum:

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

And we can solve for
and solving we got:

And from the previous result we got:

And solving we got:

And then we can find the mean with this formula:

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0
Answer:
6<em>i</em>
Step-by-step explanation:
sqrt(-121) - sqrt(-25)
11<em>i</em> - 5<em>i</em>
<u>6</u><u><em>i</em></u>
Answer:
The graph is uploaded in the attachment.
The value of x is 2.625.
Step-by-step explanation:
- let us plot f(x), g(x) on y-axis
so, f(x)=y and g(x)=y.
- the first equation can be written as y=5-2x
- the general equation of a straight is y=mx+c
( where m is the slope and c is the y-intercept )
- now comparing given equation with the general equation mentioned above, the slope of first line is -2 and its y-intercept is 5
- the slope of second equation i.e, y=(2/3)x-2 is 2/3 and its y-intercept is -2.
- now plot the graph using above information.
(y-intercept is the the coordinate of a point where the line intersects y-axis)
(slope is the angle made by the line with the x-axis)
- by seeing the graph, the value of x is 2.625.
48.00 is the answer your looking for