Multiply all terms in the first equation by 2 and all terms in the second by 3.
You should obtain:
6x + 16y = 34
-6x + 27y = 9
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43y =43, and so y = 1. Subbing 1 for y in the first eq'n, we get
3x + 8(1) = 17, or 3x = 9, or x = 3.
The solution is (3, 1).
Answer:
Step-by-step explanation:
Given
See attachment for triangles
Solving (a)
The tan of an angle is:
From the given triangle.
So, we have:
Solving (b)
The cos of an angle is:
From the given triangle.
So, we have:
Two triangles are similar if and only if all corresponding angles are equal (congruence), even if the corresponding sides are equal or not, therefore the answer is true because ΔJKL and ΔRST are similar and the statement above demands that "it must be", namely, this is a sufficient condition.
Two equivalent fractions would be 8/10
and 12/15<span />
