Question

Kim rolls a dice and flips a coin

Answer 1

Since, both the events are independent.

So, P(A+B) = P(A)×P(B)

a) P( Head & Getting a 2 ) = P( head ) × P( Getting a 2 )

$=\dfrac{1}{2}\times \dfrac{1}{6}\\\\=\dfrac{1}{12}$

b) P( Even number & Tail ) = P( Even number ) × P( Tail )

$=\dfrac{3}{6}\times \dfrac{1}{2}\\\\= \dfrac{1}{4}$

Hence, this is the required solution.