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iVinArrow [24]
3 years ago
10

I would like to create a rectangular vegetable patch. The fencing for the east and west sides costs $4 per foot, and the fencing

for the north and south sides costs only $2 per foot. I have a budget of $128 for the project. What are the dimensions of the vegetable patch with the largest area I can enclose?
north and south sides ______ ?
east and west sides ______?
Mathematics
1 answer:
loris [4]3 years ago
6 0
The answer to this question:
<span>north and south sides 16ft
east and west sides 8ft
</span>
In this question, the east and west fencing cost is $4/ft but the south and north fencing cost is $2/ft. The cost is cheaper for fencing north and south side which cost half of the east and west side. The perimeter is made by adding the south, north, east and west side.
If x = north and south fencing and y= is east and west side, then you can get this equation

cost= (south+north) * $2 + (east+west)*$4  
128=(x+x) * 2 + (y+ y) * 4
128= 4x + 8y
32= x+ 2y
x= 32-2y

The area is count by multiplying the width and length, which was x and y in this question. The formula should be:
area= length * width
area= x * y
area= (32-2y) * y
area= 32y - 2y^2

Then, you need to find the value of y needed for the maximum area.
32y- 2y^2 
32 - 2*2y=0
32= 4y
y= 8

If y=8 then
x= 32-2y
x= 32- 16= 16
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Hello!

If all of the dimensions are multiplied by 3, the volume will also be multiplied by 3.

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4 years ago
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The trainers at Atlantis Aquarium perform shows about sea life. Yesterday, they performed 4 shows in 2 hours. Today, they will p
Alecsey [184]

Answer:

3 hours

Step-by-step explanation:

Number of shows : Time taken

= 4 : 2

Today, they will perform 6 shows.

Number of shows : Time taken

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Equate both ratios to find x

4 : 2 = 6 : x

4/2 = 6/x

Cross product

4 * x = 2 * 6

4x = 12

x = 12/4

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3 years ago
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avanturin [10]

Answer:

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9t-3t+4=6t+4

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4 0
4 years ago
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Which describes the angles in triangle ABC?
luda_lava [24]

Answer:

2 acutes and one right angle

Step-by-step explanation:

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5 0
3 years ago
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assume the age of night school students is normally distributed. A simple random sample of 24 night school students had an avera
aleksley [76]
Let
n = number of data
s = standard deviation (sample)
S = standard deviation (population)

The working equations is

\frac{(n-1) s^{2} }{ x^{2}_{right} }  \ \textless \   S^{2} \ \textless \   \frac{(n-1) s^{2} }{ x^{2}_{left} }

To find x^{2}_{right}, : (1 - 0.90)/2 = 0.05

To find x^{2}_{left}, : 1 - 0.05 = 0.95

Degrees of freedom = n-1 = 24 - 1 = 23

This is shown in the figure attached. Since there is no row for df=23, we interpolate. Thus,

 x^{2}_{left} = 13.093 

 x^{2}_{right} = 35.17 


Substitute all values,

\frac{(24-1) 5.6^{2} }{ 35.17} \ \textless \ S^{2} \ \textless \ \frac{(24-1)  5.6^{2} }{ 13.093} }

Thus the answer is,

20.51\  \textless \ S^{2} \ \textless \ 55.09

5 0
3 years ago
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