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notsponge [240]
3 years ago
9

Find two numbers with a sum of 14 and a difference of 4:

Mathematics
2 answers:
erica [24]3 years ago
8 0
X=9 and y=5. Solved using substitution.

lara [203]3 years ago
4 0

Answer:

First number --> x

Second number --> y

x + y = 14 --> x = 14 - y

x - y = 4

so

14 - y - y = 4

14 - 2y = 4

2y = 10

y = 5

so

x = 14 -5

x = 9

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Answer:

B.

2.7÷0.6= 4.5/ 4 1/2

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3 0
3 years ago
The total surface area of this cuboid is 112 cm,<br>Find the value of x.<br>X cm<br>2 cm<br>10 cm​
S_A_V [24]

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x=3

Step-by-step explanation:

4 0
3 years ago
A rectangle has a perimeter of 14centimeters and an area of 10 square cm. find its dimensions
WARRIOR [948]
Perimeter is all the way around and area is l x w

So 5 x 2 would be 10.....and 5 + 5 + 2 + 2 = 14

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5 0
4 years ago
A clock strikes 2:00.what time will their needles form a right angle?
raketka [301]

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C

Step-by-step explanation:

3 0
3 years ago
Manufacture of a certain component requires three different machining operations. Machining time for each operation has a normal
faust18 [17]

Answer:

The probability is  P(X \le 70) =  0.9685

Step-by-step explanation:

From the question we are told that

The mean values is M_1 =  15 \ minutes ,  \  M_2 =  30\ minutes, \  M_3 =  20 \ minutes

The standard deviation is \sigma_1 =  1  \  minutes ,  \  \sigma_2 =  2 \ minutes  ,  \  \sigma =  1.5 \  minutes

Generally the total mean is mathematically represented as

         \= x =  \sum M_i

=>     \= x  =  15 + 30 + 20

=>    \= x =  65

Generally the total variance is  mathematically represented as

     V(x) =  \sum \sigma^2_i

=>  V(x) =  2^2 + 1^2 +  1.5^2

=>  V(x) = 7.25

Generally the total standard deviation is mathematically represented as

        \sigma =  \sqrt{V(x)}

=>     \sigma =  \sqrt{7.25 }

=>     \sigma =  2.69

Generally the probability that it takes at most 70 min of machining time to produce a randomly selected component is mathematically represented as

        P(X \le 70) =  1 - P( X > 70 )

Here  P(X > 70) =  P(\frac{X - \mu }{\sigma}  >  \frac{70 -  65}{ 2.69} )

\frac{X -\mu}{\sigma }  =  Z (The  \ standardized \  value\  of  \ X )

        P(X > 70) =  P(Z >  1.8587 )

From the z table  

  The area under the normal curve to the right corresponding to  1.8587 is

        P(Z >  1.8587 ) = 0.031535

So

      P(X \le 70) =  1 - 0.031535

=>  P(X \le 70) =  0.9685

7 0
3 years ago
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