All categories

3 years ago

Find two numbers with a sum of 14 and a difference of 4:

Mathematics

2 answers:

erica [24]3 years ago

8 0

X=9 and y=5. Solved using substitution.

lara [203]3 years ago

4 0

Answer:

First number --> x

Second number --> y

x + y = 14 --> x = 14 - y

x - y = 4

14 - y - y = 4

14 - 2y = 4

2y = 10

y = 5

x = 14 -5

x = 9

You might be interested in

16.One night, the temperature decreased at a rate of 0.6 degrees per hour. How many

Marrrta [24]

Answer:

2.7÷0.6= 4.5/ 4 1/2

mark as brailiest pls

3 0

3 years ago

The total surface area of this cuboid is 112 cm,<br>Find the value of x.<br>X cm<br>2 cm<br>10 cm

S_A_V [24]

Answer:

x=3

Step-by-step explanation:

4 0

3 years ago

A rectangle has a perimeter of 14centimeters and an area of 10 square cm. find its dimensions

WARRIOR [948]

Perimeter is all the way around and area is l x w

So 5 x 2 would be 10.....and 5 + 5 + 2 + 2 = 14

So the dimenstions are 5 x 2

5 0

4 years ago

A clock strikes 2:00.what time will their needles form a right angle?

raketka [301]

Answer:

Step-by-step explanation:

3 0

3 years ago

Manufacture of a certain component requires three different machining operations. Machining time for each operation has a normal

faust18 [17]

Answer:

The probability is $P(X \le 70) = 0.9685$

Step-by-step explanation:

From the question we are told that

The mean values is $M_1 = 15 \ minutes , \ M_2 = 30\ minutes, \ M_3 = 20 \ minutes$

The standard deviation is $\sigma_1 = 1 \ minutes , \ \sigma_2 = 2 \ minutes , \ \sigma = 1.5 \ minutes$

Generally the total mean is mathematically represented as

$\= x = \sum M_i$

=> $\= x = 15 + 30 + 20$

=> $\= x = 65$

Generally the total variance is mathematically represented as

$V(x) = \sum \sigma^2_i$

=> $V(x) = 2^2 + 1^2 + 1.5^2$

=> $V(x) = 7.25$

Generally the total standard deviation is mathematically represented as

$\sigma = \sqrt{V(x)}$

=> $\sigma = \sqrt{7.25 }$

=> $\sigma = 2.69$

Generally the probability that it takes at most 70 min of machining time to produce a randomly selected component is mathematically represented as

$P(X \le 70) = 1 - P( X > 70 )$

Here $P(X > 70) = P(\frac{X - \mu }{\sigma} > \frac{70 - 65}{ 2.69} )$

$\frac{X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ X )$

$P(X > 70) = P(Z > 1.8587 )$

From the z table

The area under the normal curve to the right corresponding to 1.8587 is

$P(Z > 1.8587 ) = 0.031535$

$P(X \le 70) = 1 - 0.031535$

=> $P(X \le 70) = 0.9685$

7 0

3 years ago