Uhh the the Nader ic clearing at the back page
Answer:

Step-by-step explanation:
Hope that this is helpful .
Have a great day.
Hello.
The answer to your question is =
12, 3 x 4 and 6 x 2.
24, 3 x 8 and 6 x 4.
36, 3 x 12 and 6 x 6.
48, 3 x 16 and 6 x 8.
So it's pretty much everything except for 32.
Have a great day!
Answer:
(a) 
(c) 
Step-by-step explanation:
(a) To find verify the answer we need to multiplying the equation

Thus, this statement is true.
(b) To find verify the answer we need to multiplying the equation 

Hence, the given statement is false.
(c) To find verify the answer we need to multiplying the equation 

Hence, the given statement is true.
(d) To find verify the answer we need to multiplying the equation

Hence, the given statement is false.
Answer: 9
is the value of "x".