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netineya [11]
3 years ago
12

Which series of transformations maps △ABC to △A′B′C′?

Mathematics
2 answers:
miskamm [114]3 years ago
7 0
The answer is C, have a great day!
lys-0071 [83]3 years ago
5 0
The answer is B.

The triangle is reflected over the X axis (horizontal axis) and shifted to the left 1 unit.

Hope this helps :)
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Mean:<br>median:<br>mode:<br>plz help
lbvjy [14]

In your shoes I would look up "mean," "median" and "mode" to be certain of what they mean. That knowledge (or lack of it) will certainly affect your course grade.

Rearrange the nine given numbers in ascending order: 135, 135, 142, 150, 168, 173, 178, 184, 193.

The mode is the number that shows up most often. That'd be 135. No other number shows up twice.

The median is the middle number of the rearranged seet. That'd be 168.

The mean is the arithmetic average of the 9 numbers. To find that, add up the numbers and divide your sum by 9:

135+135+142+150+168+173+178+184+193

mean: ---------------------------------------------------------------- = 162

9

7 0
3 years ago
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Y/0.5=16<br><br> Please solve the equation ‍♀️
sweet-ann [11.9K]

Answer:

y=8

Step-by-step explanation:

y/0.5=16

multiply each side by 0.5 and you get y=8

5 0
3 years ago
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What areC12, C31, and C22 of matrix C?
Liono4ka [1.6K]

Compute the sum to simplify C :

C = \begin{bmatrix}16-0.5 & 9+0 \\ -3+5 & 0 + 8 \\ 4-3 & -10+14\end{bmatrix} = \begin{bmatrix}15.5 & 9 \\ 2 & 8 \\ 1 & 4\end{bmatrix}

Now, c_{ij} is the entry of the matrix in row i and column j, so

C = \begin{bmatrix}15.5 & \boxed{9} \\ 2 & 8 \\ 1 & 4\end{bmatrix} \implies c_{12} = 9

C = \begin{bmatrix}15.5 & 9 \\ 2 & 8 \\ \boxed{1} & 4\end{bmatrix} \implies c_{31} = 1

C = \begin{bmatrix}15.5 & 9 \\ 2 & \boxed{8} \\ 1 & 4\end{bmatrix} \implies c_{22} = 8

5 0
2 years ago
What's the perimeter of the rectangle shown below
Eva8 [605]

There is no rectangle shown below. 

Maybe that's why you're having trouble
with this problem.
3 0
3 years ago
The function d(t) =300,000t represents the distance (in kilometers) that light travels in t seconds
3241004551 [841]

We were given the distance, d as a function of time, t.

d(t)=300,000t.

To find d(15), we put t=15, in to


d(t)=300,000t


This implies that,

d(15)=300,000(15)


d(15)=4,500,000

This means that in 15 seconds light covers a distance of 4,500,000 kilometers

5 0
3 years ago
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