The distance covered by the hare and the tortoise in t seconds are 8t and 5t respectively. (Simple Speed-Distance-Time relation)
The tortoise gets a 510m headstart so at t=0 is 1490m.
The functions representing the distance of both of them from the finish line is,
F(x)=2000-8t,. for hare
G(x)=1490-5t,. for tortoise
The maximum value can be determined by taking the derivative of the function.
(dh/dt) [h(t)] = h'(x) = -9.8t + 6
Set h'(x) = 0 to find the critical point
-9.8t + 6 = 0
-9.8t = -6
t = 6/9.8
Plug the time back into the function to find the height.
h(6/9.8) = -4.9(6/9.8)^2 + 6(6/9.8) + .6
= 2.4
And I don't understand your second question.
Answer:
The answer to your question is:
Step-by-step explanation:
1.-






2sec
2.-
sec²x - tanxsecx






Answer: x = 6.46153846
Step-by-step explanation:
We are given the equation <em>13x - 4 +100 = 180</em>, and we must find the value of <em>x</em>. In order to do that get x on on one side by itself and a constant on the other side by itself.
This first step is to combine like terms. <em>13x</em> is by itself. <em>-4 + 100 = 96</em>. This gives us the equation <em>13x +96 = 180</em>.
In order to get <em>x </em>by itself, subtract 96 from each side of the equation. This gives us the equation 13x = 84.
Next, divide each side by 13 to find x. This gives us x = 6.46153846




Hope this helps! Have a nice day!