1) Since it was 0 years when the college opened, we put x=0 and we get
T=12000
2) 0.03%
3) From 1990 to 2020, it is 30 years. Thus, x=30.
T=12000*(1.03)^30
For calculations for the 2nd point, refer to the picture.
Hope this helps!
For future whenever you solve these type, just know that x is a variable and tree have to insert out own value for x according to the questions’s demand.
Answer:
The 99% confidence interval for the true mean number of hours a union member is absent per month is (0 hours, 16.5125 hours).
Step-by-step explanation:
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of .
So it is z with a pvalue of , so
Now, find M as such
In which s is the standard deviation of the sample.
So
The lower end of the interval is the mean subtracted by M. So it is 7.5 - 9.0125 = -...
There is not a negative number of hours. So the lower end of the interval is 0 hours.
The upper end of the interval is the mean added to M. So it is 7.5 + 9.0125 = 16.5125 hours.
The 99% confidence interval for the true mean number of hours a union member is absent per month is (0 hours, 16.5125 hours).