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3 years ago

Sole x/5 = 10 1.x=50 2.x=2 3.x=15 4.x=5

Mathematics

1 answer:

Anarel [89]3 years ago

3 0

The answer is 1.
( x = 50)

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Six times a number is greater than 20 more than that number. What are the possible values of that number?

Alex73 [517]

Answer:

6x > x + 20,

x > 4

X belongs to a set of real numbers [0, +infinity)

Step-by-step explanation:

6x > x + 20

5x > 20

x > 4

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3 years ago

Put the following numbers in order from least to greatest.-8, 15, 9, -6, -3, 12, 0, -4

kati45 [8]

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Step-by-step explanation:

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3 years ago

-7-(-9) =<br> What is the answer to the question

Rudiy27

Answer: 2

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3 years ago

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How do you solve what is 2/3 of 3/4?

grin007 [14]

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0.5

Step-by-step explanation:

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2 years ago

evaluate the line integral ∫cf⋅dr, where f(x,y,z)=5xi−yj+zk and c is given by the vector function r(t)=⟨sint,cost,t⟩, 0≤t≤3π/2.

meriva

We have

$\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} \vec f(\vec r(t)) \cdot \dfrac{d\vec r}{dt} \, dt$

and

$\vec f(\vec r(t)) = 5\sin(t) \, \vec\imath - \cos(t) \, \vec\jmath + t \, \vec k$

$\vec r(t) = \sin(t)\,\vec\imath + \cos(t)\,\vec\jmath + t\,\vec k \implies \dfrac{d\vec r}{dt} = \cos(t) \, \vec\imath - \sin(t) \, \vec\jmath + \vec k$

so the line integral is equilvalent to

$\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} (5\sin(t) \cos(t) + \sin(t)\cos(t) + t) \, dt$

$\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} (6\sin(t) \cos(t) + t) \, dt$

$\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} (3\sin(2t) + t) \, dt$

$\displaystyle \int_C \vec f \cdot d\vec r = \left(-\frac32 \cos(2t) + \frac12 t^2\right) \bigg_0^{\frac{3\pi}2}$

$\displaystyle \int_C \vec f \cdot d\vec r = \left(\frac32 + \frac{9\pi^2}8\right) - \left(-\frac32\right) = \boxed{3 + \frac{9\pi^2}8}$

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2 years ago