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BigorU [14]
3 years ago
7

The diameter of a circle is 19 inches. If the diameter is extended 5 inches beyond the circle to point C, how long is the tangen

t segment from point C to the circle? Use the figure below to help guide your response. Explain your answer and show all work.

Mathematics
2 answers:
Anna [14]3 years ago
6 0
The tangent segment from point C is 5 inches from the circle
zysi [14]3 years ago
6 0

Answer:

Exact Length = 2*sqrt(30)

Approximate Length = 10.95445

======================================================

Work Shown:

(tangent)^2 = (external secant)*(whole secant)

(CD)^2 = (CB)*(CA)

(CD)^2 = (CB)*(CB+BA)

x^2 = 5*(5+19)

x^2 = 120

x = sqrt(120)

x = sqrt(4*30)

x = sqrt(4)*sqrt(30)

x = 2*sqrt(30)  .......... exact length

x = 10.95445 ............. approximate length

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1st q answer is f(x) is one- to -one function and 2nd q answer is 2

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How do you solve for x <br><br>the similarity statement is abc~ xyz​
tensa zangetsu [6.8K]

Answer:

m<X= 36.87 degrees

Step-by-step explanation:

Since the triangle abc and xyz are similar, hence;

m<C = m<Y

90 = x - 5

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90+5 = x-5+5

95 = x

Swap

x = 95

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m<Y = 95 - 5

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8 0
3 years ago
Você é um comandante de uma espaçonave. Sua missão é chegar até Alfa Centauro em cinco anos. A distância do Sol até Alfa Centaur
Deffense [45]

Answer:

The spaceship will get to Alpha Centaur in time

Step-by-step explanation:

<u><em>The complete question in English is</em></u>

You're the commander of a spaceship. Your mission is to reach Alpha Centaur  in five years. The distance from the sun to Alpha Centaur is 2.5 x 10^13 miles. The distance  from Earth to Sun is approximately 9.3 x 10^7

miles. Your spaceship can travel  at the speed of light. You know that light can travel a distance of 5.88 x 10^12  miles in a year. Can you get to Alpha Centaur in time?

step 1

Find the time it takes for the spaceship to travel from Earth to the Sun

The distance from the Earth to Sun is equal to

9.3*10^7\ miles

The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

so

using a proportion

\frac{5.88*10^{12}\ miles}{1\ year}=\frac{9.3*10^7\ miles}{x}\\\\x=(9.3*10^7)/5.88*10^{12}\\\\x=1.58*10^{-5} \ years

This time is very small in years

Convert to minutes

1.58*10^{-5} \ years=1.58*10^{-5} (365)(24)(60)=8.3\ min

step 2

Find the time it takes for the spaceship to travel from the Sun to Alpha Centaur

The distance from the the Sun to Alpha Centaur is equal to

2.5*10^{13}\ miles

The spaceship can travel  at the speed of light

The light can travel a distance of 5.88*10^{12}\ miles in a year

so

using a proportion

\frac{5.88*10^{12}\ miles}{1\ year}=\frac{2.5*10^{13}\ miles}{x}\\\\x=(2.5*10^{13})/5.88*10^{12}\\\\x=4.25\ years

4.25\ years< 5\ years

therefore

The spaceship will get to Alpha Centaur in time

3 0
3 years ago
Ed spoke to his cousin in Australia, who told him it was 28°C that day Ed wasn't sure if that was hot or cold, so he
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Answer:

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Step-by-step explanation:

hope this helps you man

4 0
3 years ago
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Please help me with this page
Maurinko [17]
Well i can help u with one problem 7 I don’t think it is A cause if u multiple 17.50 by 2 u will get $35.00 and when u add $43.00 that will be $78
So I think 7. Would be B

7. B
6 0
3 years ago
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