Answer: P = $ 12000
r = 14%
t = 1 (for first year)
I = (P X r X t)/100
∴ I = (12000 X 14 X 1)/100
= 120 X 14
= $ 1680 <---------- (Interest on loan at the end of first year)
∴ Total amount owing at the end of first year = (P + I)
= (12000 + 1680)
= $ 13680
Repayment = $ 7800
Amount still outstanding (at the start of second year) = 13680 - 7800
= $ 5880
Interest on the outstanding amount at the end of second year,
P (new) = $ 5880
r (same) = 14%
t = 1 (for the current second year)
∴ I = (P X r X t)/100
= (5880 X 14 X 1)/100
= 82320 / 100
= $ 823.2 <-------------------------- (Interest on outstanding amount at the end of second year)
Answer:
you add an image
Step-by-step explanation:
It’s the 5 and 6 numbers 152 and 144
Answer:
45.6 cm
Step-by-step explanation:
Let X be the hypotenuse.
(36)^2 + (28)^2 = X^2
X = 45.6 cm
-x - 50/10 = -2x + 150/10 <=== ur equation
-x + 2x = 150/10 + 50/10
x = 200/10 reduces to 20
