<span>0.05 arc-second = 1 degree/72000 = (pi
radians)/(180*72000) = 2.424 x 10^(-7) radians</span>
<span>The distance is roughly: </span>
<span>R*(theta) = (600 light-years)*2.424 x 10^(-7) = 0.00014544 light-years = 1.275
light-hours = (3600 seconds)*(3 x 10^8 m/s)*(1.275) = 1.38 x 10^12 meters.</span>
Since this is a right triangle, you can use the main trig functions sin, cos, and tan. We must use sin for this problem because sin= opp/hyp. Plug in the numbers to this function. Sin (53) = a/25. Thus when you cross multiply, you get a= sin (53) x 25. When you plug it into a calculator the answer should come out to 19.97
It’s 500.
Explanation: If you would solve for that m^3 over m^2, you’d get m^1. So, m^1 is the square root of m^2, so you just take the square root of 250,000 to get 500. I really hope this helps!
