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castortr0y [4]
3 years ago
5

The three vertices of △ABC are in quadrant I. If △ABC is reflected in the x-axis, its image will lie in quadrant

Mathematics
2 answers:
Kipish [7]3 years ago
7 0

The three vertices of △ABC are in quadrant I. If △ABC is reflected in the x-axis, its image will lie in quadrant IV

Hope it helps

SSSSS [86.1K]3 years ago
3 0

Quadrant I is the top right section of a graph. The x-axis is the bold horizontal line usually in the middle of the graph. If you reflect a shape over it, it means you flip the figure across it to the other side.

The opposite side of Quadrant I is Quadrant IV, so the image of triangle ABC will lie in Quadrant IV.

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Suppose the following regression equation was generated from the sample data of 50 cities relating number of cigarette packs sol
frez [133]

Answer:

A) According to the regression equation, regardless of whether or not smoking is allowed in bars, the number of cigarette packs sold per 1000 people decreases by approximately 1424 for each additional dollar of cigarette tax.

Step-by-step explanation:

Given the regression equation:

PACKS i= 57221.431732 − 1423.696906TAXi + 155.441784BARSi + eᵢ.

BARS i= 1 if city i allows smoking in bars

BARSi = 0 if city i does not allow smoking in bars

R2 = 0.351292

P-value = 0.086529

Conlusion:

Simnce p value, 0.0865 is greater than level of significance, 0.05, BARS is not significant. Thus, allowing smoking in bars increase cigarette sales, since the coefficient of BARS is positive.

Correct answer is option A.

According to the regression equation, regardless of whether or not smoking is allowed in bars, the number of cigarette packs sold per 1000 people decreases by approximately 1424 for each additional dollar of cigarette tax.

4 0
3 years ago
A negative times a negative equals a positive true or false
kobusy [5.1K]
True, when the signs are different the answer is a negative, but when the signs are the same the answer is a positive.
5 0
3 years ago
Read 2 more answers
Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost $35 and same-day tickets $30 c
Marina CMI [18]

Answer:

The number of same-day tickets sold is 15

The number of advance ticket sold is 20

Step-by-step explanation:

Given as :

The cost of each Advance ticket = $35

The cost of each same-day ticket = $30

The total cost of the tickets sold = $1150

The total number of tickets sold = 35

Let The number of advance ticket sold = a

And The number of same-day ticket sold = s

Now, According to question

The total number of tickets sold =The number of advance ticket sold + The number of same-day ticket sold

I.e a + s = 35                   .....A

The total number of tickets sold = The cost of each Advance ticket × The number of advance ticket sold + The cost of each same-day ticket × The number of same-day ticket sold

I.e $35 a + $30 s = $1150

or, 35 a + 30 s = 1150               .......B

Now, solving eq A and B

35 × ( a + s) - ( 35 a + 30 s ) = 35 × 35 - 1150

or, ( 35 a - 35 a ) + ( 35 s - 30 s ) = 1225 - 1150

or, 0 + 5 s = 75

∴  s = \frac{75}{5}

I.e s = 15

So, The number of same-day tickets sold = s = 15

Put the value of s in Eq A

So, a + 15 = 35

∴  a = 35 - 15

I.e a = 20

So, The number of advance ticket sold = a = 20

Hence The number of same-day tickets sold is 15

And  The number of advance ticket sold is 20   Answer

7 0
4 years ago
Please I need help in this
belka [17]

Answer:

Point C

Step-by-step explanation:

negative means go left on the x axis and negative on the y axis means go down. Sorry if this explanation doesn't help much.

3 0
3 years ago
Read 2 more answers
Alan has forgotten his 4-digit PIN code.He knows it begins with a 6 and the 4 digits make an even number.How many different sets
Oxana [17]

Answer:

500.

Step-by-step explanation:

The last digit must end with 0, 2, 4, 6, 8   for the Pin code to be even.

The middle 2 digits may be any numbers.

So if the last number is 0 Then there are 10*10 = 100 possible PIN codes.

So  as there are 5 possible last digits , the total  possible sets of digits

= 5 * 100

= 500.

4 0
3 years ago
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