All categories

3 years ago

The three vertices of △ABC are in quadrant I. If △ABC is reflected in the x-axis, its image will lie in quadrant

Mathematics

2 answers:

Kipish [7]3 years ago

7 0

The three vertices of △ABC are in quadrant I. If △ABC is reflected in the x-axis, its image will lie in quadrant IV

Hope it helps

SSSSS [86.1K]3 years ago

3 0

Quadrant I is the top right section of a graph. The x-axis is the bold horizontal line usually in the middle of the graph. If you reflect a shape over it, it means you flip the figure across it to the other side.

The opposite side of Quadrant I is Quadrant IV, so the image of triangle ABC will lie in Quadrant IV.

You might be interested in

Help! Mathematics answer? Will give brainliest and some good points, Algebra I

skad [1K]

The answer is B.

Hope it helps!

8 0

2 years ago

Jessica and Maria got to the supermarket to buy fruit. Jessica

Burka [1]

Answer:$0.25 per apple

$0.30 per orange

Step-by-step explanation:

I knowwww iM aMbitious and i helped 126

people

3 0

2 years ago

The football team has a total of 50 jerseys. There are 35 medium-sized jerseys. What percent of the jerseys are medium-sized j

Mariulka [41]

Hello,

This problem can be simply solved by putting everything into fractions. Since there's a total of 50 shirts but 35 of them are medium sized then the fraction would be 35/50. You're trying to find the percentage so the 2nd fraction would be out of 100 so it would be ?/100.
35 ?
---- = ----
50 100
Now you diagonal multiplication then downwards division.
100 x 35=3500
3500/50=70
So your answer is 70%!! :D
Hope this helps a bunch!!!

4 0

3 years ago

A figure is shown with the given dimensions.

Illusion [34]

Answer:

$\blue{A = 24~ft^2}$

Step-by-step explanation:

This figure is a trapezoid with bases of 10 ft and 6 ft and height of 3 ft.

$A = \dfrac{b_1 + b_2}{2}h$

$A = \dfrac{10~ft + 6~ft}{2} \times 3~ft$

$\blue{A = 24~ft^2}$

4 0

2 years ago

A rectangular pool 12 meters by 8 meters is surrounded by a walkway of width x meters. At what

Thepotemich [5.8K]

X=3

x is the width of the sidewalk
The outside dimensions of the walkway are 12 + 2x by 8 + 2x
The total area is (12 + 2x)(8 + 2x)
The total area minus the area of the pool should be equal to the area of the pool

Hoped this helped!

8 0

2 years ago