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Lelu [443]
2 years ago
7

PLEASE!! I REALLY NEED YOUR HELP!!

Mathematics
2 answers:
KatRina [158]2 years ago
5 0

Answer:

9.09090909%

Step-by-step explanation:

Rufina [12.5K]2 years ago
5 0

Answer:

Mon had 100 kg of water, dumped it into 10kg of pure salt, namely 100% salt, what happened?  well, it ended up with 100kg + 10kg, or 110kg of saline solution, off which 10kg are just salt.

so, if we take the 110kg to be the 100%, what is 10kg in percentage off of it?  namely the salty part.

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Alicia is writing the program for a video game.
ICE Princess25 [194]

Step-by-step explanation:

<u>A.-6-3 = -9</u>

0+4 = 4  

(-9,4)

<u>B.3-3 = 0</u>

-4+4 = 0  

(0,0)

7 0
3 years ago
Can I get some help with proofs?<br> Picture is attached
aleksandr82 [10.1K]

Give a reason for each step of the proof. 

Given: <1 and <2 are complimentary 

<1 is congruent to <3, 

<2 is congruent to <4 

Prove: <3 and <4 are complimentary 

Statements: Reasons: 

1. <1 and <2 are complimentary 1.Given 

2. m<1 + m<2=90* 2.<u>DEFINITION OF COMPLEMENTARY ANGLES</u>

3. <1 is congruent to <3, <2 is congruent to <4 3.__GIVEN______ 

4. m<1=m<3, m<2=m<4 4.<u>DEFINITION OF CONGRUENT ANGLES_</u>

5. m<3 + m<2=90* 5. <u>SUBSTITUTION PROPERTY (m<1 is replaced by m<3.) </u>

6. m<3 +m<4=90* 6. <u>DEFINITION OF COMPLEMENTARY ANGLES </u>

7. <3 and <4 are complimentary 7.<u> DEFINITION OF COMPLEMENTARY ANGLES</u>

8 0
3 years ago
A chemist wants to make 100 liters of a 44% acid solution. She has solutions that are 20% acid and 60% acid.
alexgriva [62]

the first solution is 20% acid, and say we'll be using "x" liters, so how many liters of just acid are in it?  well 20% of "x" or namely 0.2x.  Likewise for the 60% acid solution, if we had "y" liters of it, the amount of only acid in it is 0.6y.

\begin{array}{lcccl} &\stackrel{solution}{quantity}&\stackrel{\textit{\% of }}{amount}&\stackrel{\textit{liters of }}{amount}\\ \cline{2-4}&\\ \textit{1st solution}&x&0.20&0.2x\\ \textit{2nd solution}&y&0.60&0.6y\\ \cline{2-4}&\\ mixture&100&0.44&44 \end{array}~\hfill \begin{cases} x+y=100\\\\ 0.2x+0.6y=44 \end{cases}

x+y=100\implies y=100-x~\hfill \stackrel{\textit{substituting on the 2nd equation}}{0.2x+0.6(100-x)=44} \\\\\\ 0.2x+60-0.6x=44\implies -0.4x+60=44\implies -0.4x=-16 \\\\\\ x=\cfrac{-16}{-0.4}\implies \boxed{x=40}~\hfill \boxed{\stackrel{100-40}{y=60}}

7 0
2 years ago
I don’t understand this can someone help?
Anon25 [30]

Answer:

no inglis sorry Xdxdxd y no se entiende xd

5 0
2 years ago
Read 2 more answers
4(x-4) solve and why I don't get it
Rudiy27
4 will multiply inside that brackets so
4(x-4)=4x-4
7 0
2 years ago
Read 2 more answers
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