Answer:
t=14
v=13
q=12
s=23
w=-4
x=28
Step-by-step explanation:
we know that the universal set =100
so, everything in it must add up to 100
first, from the information given to us,
t= n(A n C)= 14
v=n(B n C)= 13
to find q
we know from our guide that n(A) =40
which means everything inside A will add up to 40
therefore,
q + 7 + 7 + t = 40
and we already know that t = 14
so, that will be;
q + 7 + 7 + 14 = 40
therefore, q = 12
to find s,
we all know that n(B) = 50
which means that everything inside B will be equal to 50
therefore,
s + 7 + 7 + v = 50
and we know that v = 13
therefore,
s + 7 + 7 + 13 = 50
and s will end up to be = 23
to find w,
we know that n(C) = 30
so, everything in C end up to be all equal to 30
therefore,
t + 7 + w + v = 30
from our solution, t = 14, v = 13
so,
14 + 7 + w
9/10 + 7/100
find the common denominator for 9/10 which is 100
multiply by 10 for 9/10
(9)(10)=90
(10)(10)=100
90/100+7/100
Answer:
97/100
Answer:
<em>The new mixture is 49% peanuts.</em>
Step-by-step explanation:
The first batch of 9 lb of mixed nuts contains 55% peanuts. This means the quantity of peanut is:
9*55/100=4.95 lb
The second batch of 6 lb of mixed nuts contains 40% peanuts. This means the quantity of peanut is:
6*40/100=2.4 lb
The total quantity of peanut in the mix is
4.95 lb + 2.4 lb =7.35 lb
There are 9 lb + 6 lb = 15 lb of mix. Thus, the percent of peanut in the mix is:
7.35 / 15 * 100 = 49%
The new mixture is 49% peanuts.
Step-by-step explanation:
-8x+5 > 21
Minus 5 from both sides
-8x > 16
Then divide 8 from both sides (also I am pretty sure the sign would change because you are dividing by a negative number)
x < -2
So the answer is x is less than or equal to -2
or C
I hope this helps!
Answer: a) -24
b) 
c) 4
Step-by-step explanation:
a) To determine the value of (fg)', use the product rule of derivative, i.e.:
(fg)'(x) = f'(x)g(x) + f(x)g'(x)
(fg)'(5) = f'(5)g(5) + f(5)g'(5)
(fg)'(5) = 6(-5) + 3(2)
(fg)'(5) = -24
b) The value is given by the use of the quotient rule of derivative:
![(\frac{f}{g})'(x)=\frac{f'(x)g(x)-f(x)g'(x)}{[g(x)]^2}](https://tex.z-dn.net/?f=%28%5Cfrac%7Bf%7D%7Bg%7D%29%27%28x%29%3D%5Cfrac%7Bf%27%28x%29g%28x%29-f%28x%29g%27%28x%29%7D%7B%5Bg%28x%29%5D%5E2%7D)
![(\frac{f}{g})' (5)=\frac{f'(5)g(5)-f(5)g'(5)}{[g(5)]^2}](https://tex.z-dn.net/?f=%28%5Cfrac%7Bf%7D%7Bg%7D%29%27%20%285%29%3D%5Cfrac%7Bf%27%285%29g%285%29-f%285%29g%27%285%29%7D%7B%5Bg%285%29%5D%5E2%7D)
c) ![(\frac{g}{f})'(5)=\frac{g'(5)f(5)-g(5)f'(5)}{[f(5)]^{2}}](https://tex.z-dn.net/?f=%28%5Cfrac%7Bg%7D%7Bf%7D%29%27%285%29%3D%5Cfrac%7Bg%27%285%29f%285%29-g%285%29f%27%285%29%7D%7B%5Bf%285%29%5D%5E%7B2%7D%7D)
