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9966 [12]
3 years ago
14

Which expression has a value greater than 43?​

Mathematics
1 answer:
erica [24]3 years ago
8 0

Answer:

44 Please Mark Me Brainliest

Step-by-step explanation:

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Which expressions are equivalent to -2(5x-3/4)?
kogti [31]

Answer:

-10x+3/2

Hope this helps

6 0
3 years ago
Please help me out with this question
sleet_krkn [62]

Answer:

0.31%

Step-by-step explanation:

Just look at the graph my man

5 0
3 years ago
= table shows a hot air balloon's height h, in feet, during a descent at various times t, in seconds.
denpristay [2]

Answer:

A. Slope is -12 feet per second

B. Yes, it is constant.

<u>Skills needed: Linear Equations, Substitution and Division</u>

Step-by-step explanation:

1) Solving Part A (we need to find the slope):

  • The slope is \frac{y_2-y_1}{x_2-x_1} --> y_1, y_2, x_1, and x_2 are all values from the table. We know that the left column is the x-values, and the right column is the y-values as that is the conventional way of depicting them.

2) Using the y-values of 1150 and 1090, and their corresponding x-values (5 and 10 respectively), we can get the slope:

- \frac{y_2-y_1}{x_2-x_1} ==> \frac{1090-1150}{10-5} ==> 1090-1150=-60, 10-5=5 ==> \frac{-60}{5}

\frac{-60}{5} =-12, so the slope is -12.

==================================================================

1) Part B (analysis)

We can see that no matter what 2 y-values and their corresponding x values we use, the slope always is the same. This means that the rate of change is constant.

8 0
3 years ago
Algebra math word problems
levacccp [35]

7. 8n=40
n=5 bracelets
8. 20g=300
g=15 rounds of golf

3 0
3 years ago
A rectangular box 4 meters long, 3 meters wide and 2 meters tall. On the box is a cat, and the box is floating in water such tha
Vikentia [17]

Answer:

Mass of the cat  = 16800kg

Step-by-step explanation:

The volume of the box = its length * its breath * its height- 4m × 3m × 2m = 24m^{3}

The standard density of water is 1000 Kg/m^{3}

By Archimedes principle, the mass of a body  floating body is equivalent to the mass of the volume liquid displaced

in this case we have

Mass of water displaced = Density of the water × Volume of the water  displaced =   1000 Kg/m^{3} × 24m^{3} = 24000kg

The mass of the box = Box density × Box volume = 24m^{3} × 300kg/m^{3} = 7200 kg Hence the mass of water displaced = mass of the foating box + mass of th cat

24000kg =  mass of cat +7200kg

mass of cat = 24000kg - 7200kg = 16800kg

8 0
4 years ago
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