The answer would be (x+1)(x+3)
Ab = (7x-6) → b = (7x-6)/a (1)
bc = (12-2x) → b = (12-2x)/c (2)
Since (1) = (2) → (7x-6)/a = (12-2x)/c OR a/c = (7x-6)/(12-2x) (3)
Multiply both numerators of (3) by the SQUARE of their respective denominators;
(a*c²)/c = (7x-6)(12-2x)²/(12-2x)
Now simplify:
ac = (7x-6)(12x-2x) or ac = -14x² + 96x - 72
Answer:
I assume you mean 16^(1/3) i.e. the cube root of 16
I am also assuming you mean the real cube root because, as you may know, every non-zero real number has three cube root - one real and two complex conjugates.
Since 16 = 8 x 2 and 8 = 2³ then (2³ x 2)^1/3 = (2³)^1/3 x 2^1/3 = 2 x 2^1/3
You might check that the cube root of 16 is about 2.52 which is twice the cube root of 2
Step-by-step explanation:
Answer:
True
Step-by-step explanation:
