All categories

3 years ago

A rectangle has length 9.3 x 102 cm and width 8.4 x 102 cm. What is the area of the rectangle?

Mathematics

2 answers:

Archy [21]3 years ago

7 0

Answer:

781200 cm or 7.81200x10^5 cm

Step-by-step explanation:

Here, you need to solve it with the area equation.

For a rectangle, it's base x height.

In this case, your base will be it's length $9.3x10^{2} cm$ = $930cm\\$ , and its height will be width $8.4x10^{2} cm$ = $840cm$ .

An then you can solve it

$(9.3x10^{2})*(8.4x10^{2})=781200 cm = 7.81200x10^{5}$

PolarNik [594]3 years ago

3 0

9.3x8.4 = 78.12

10^2 x 10^2 = 10^4

answer = 7.812 x 10^5

You might be interested in

Last year, Raina had $10,000 to invest. She invested some of it in an account that paid 9% simple interest per year, and she inv

kaheart [24]

Answer:

7000 in the account that paid 9% interest rate and 3000 in the account that paid 8% interest rate

Step-by-step explanation:

Let $x be invested in account 1 and $(10000-x) in the second account

Then, 870=x*9/100+(10000-x)*8/100

x=$7,000.

4 0

2 years ago

4(2x+7) +3 (2x+7) but (2x+7) is equal to 2

vodomira [7]

Use the distributive property to get 8x+28+6x+21 then combine 8x and 6x and also combine 28 and 21 to get 14x+49, do u need to go further or?

6 0

3 years ago

Brian borrowed a 20 foot extension ladder to use when he paints hes house. If he sets the base of the ladder 6 feet from the hou

iren [92.7K]

Answer:

It is 20.9feet

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A tangent line and its normal line have a point of tangency to the function f(x) at (x,y). If the slop of the normal line is m=(

alekssr [168]

Answer:

$\displaystyle \\\left(\frac{49}{900},\frac{3761}{900}\right)$ or approximately (0.544, 4.179)

Step-by-step explanation:

A function and its tangent lines intersect when their slopes are the same. Find the x-coordinate when the slope of f(x) is equal to 8/7 by taking the derivative of f(x):

$\displaystyle\\f(x)=\sqrt{x}-x+4\\f'(x)=\frac{1}{2}\cdot\frac{1}{\sqrt{x}}-1=\frac{1}{2\sqrt{x}}-1$

Set $f'(x)$ equal to 8/7 and solve for x:

$\displaystyle \\\frac{1}{2\sqrt{x}}-1=\frac{8}{7},\\x=\frac{49}{900}$

Therefore, $f(x)$ will intersect at a point of tangency with a line of slope 8/7 at x=49/900. Plug in x=49/900 into $f(x)$ to get the y-coordinate:

$\displaystyle\\y=\sqrt{x}-x+4 \vert_{x=49/900}=\frac{3761}{900}$

⇒Answer: (49/900, 3761/900) or approximately (0.544, 4.179)

5 0

2 years ago

Giselle spent 7/10 of her money on a book and 10/100 of her money on food. What fraction of her money did she spend altogether?

aleksklad [387]

Answer:

80/100 or 80%

Step-by-step explanation:

7/10 = 70/100

70/100 + 10/100 = 80/100

8 0

2 years ago

Read 2 more answers