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scoray [572]
4 years ago
9

What is $9 discounted to $4

Mathematics
1 answer:
Dafna11 [192]4 years ago
4 0

Answer:

123

Step-by-step explanation:

acasn cjhnckjasnjakwfn idk

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Someone please help me
Dovator [93]
<h3>Answer:  B) 2</h3>

=========================================================

Explanation:

Take away the four white small squares on the left side. To balance things out, you have to add 4 black squares to the right side.

Also, take away the two white long rectangles from the right side. To balance this out, you have to add 2 gray long rectangles to the left side.

You should have:

  • 5 gray rectangles, and no squares (of any color) on the left side
  • 10 black squares, no long rectangles (of any color), on the right side

From here you'll group up the 10 black squares so that you'll have 2 black squares per gray rectangle.

This means the solution is 2.

-------------------------------------

If you're curious about the algebraic way to solve, then you could do this:

3x-4 = -2x+6

3x+2x = 6+4

5x = 10

x = 10/5

x = 2

This method doesn't require us to use the visual model.

5 0
3 years ago
For a back to school sale the price of a calculator is reduceded from 70% to $59.50. What is the answer
Leona [35]
Thats what i came up with $25.50
7 0
3 years ago
Need the answer times running out on the test
boyakko [2]

B is the answer

Expand factors

Reorder multiply

Transform

Answer!

6 0
2 years ago
Seven than the product of 5 and a number
weqwewe [10]
Do you mean 7 more than the product of 5 and a number? If so the answer is... y=7+5x
5 0
3 years ago
Read 2 more answers
The owner of Maumee Ford-Mercury-Volvo wants to study the relationship between the age of a car and its selling price. Listed be
nadya68 [22]

Answer:

a= 13.15 years

b= -0.62 years/$

Step-by-step explanation:

Hello!

Given the variables

Y: Age of a used car. (years)

X: Price of a sold used car. ($000)

The linear regression model is:

E(Y)= α + βXi

The estimated equation is:

^Y= a + bXi

a= (\frac{sumY_i}{n} ) - b(\frac{sumX_i}{n} )

a= 13.15 years

b= \frac{(sumX_iY_i-\frac{(sumX_i)(sumY_i)}{n} }{sumX_i^2-(\frac{(sumX_i)^2}{n} )}

b= -0.62 years/$

Then ^Y= 13.15 - 0.62Xi

Mean Y= 8.92

Mean X= 6.91

∑Y= 107

∑Y²=1009

∑X=82.90

∑X²=615.29

∑XY=712.9

Hope it helps!

5 0
4 years ago
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