Hi!
<u>Given these two equations:</u>
We want to solve using the substitution method. Knowing that x is equal to y + 8, we can simply plug in 'y + 8' in for x in the second equation, like so:
Combine like terms on both sides:
Subtract y from both sides:
Subtract 8 from both sides:
Now, we can simply plug the y value in to the first equation, and solve for x:
Simplify:
<h3>
Therefore, x is equal to 12 and y is equal to 4.</h3>
<u>Learn more about the substitution (and also elimination!) method here:</u>
brainly.com/question/14619835
a. 1.15
b. 6.20 divided by 4 = 1.55
c. 5 divided by 4 = 1.25
d. 5.50 divided by 5 = 1.1
D is correct
Answer:
45
Step-by-step explanation:
These work problems are always done in terms of fractions ie if both (Kevin & Eric) took 30mins to mow and Kevin took 1.5hrs (90mins) alone then we can make an equation like below
1/time took for both = 1/time took for Kevin + 1/time took for Eric
1/30 = 1/90+1/x ==> calling time took for Kevin x
solving the above 1/x = 1/30-1/90
1/x=2/90
x=45
Answer:
probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3
Step-by-step explanation:
First of all;
Let B1 be the event that the card with two red sides is selected
Let B2 be the event that the
card with two black sides is selected
Let B3 be the event that the card with one red side and one black side is
selected
Let A be the event that the upper side of the selected card (when put down on the ground)
is red.
Now, from the question;
P(B3) = ⅓
P(A|B3) = ½
P(B1) = ⅓
P(A|B1) = 1
P(B2) = ⅓
P(A|B2)) = 0
(P(B3) = ⅓
P(A|B3) = ½
Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;
P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]
Thus;
P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]
P(B3|A) = (1/6)/(⅓ + 0 + 1/6)
P(B3|A) = (1/6)/(1/2)
P(B3|A) = 1/3
